Your equation is presented in by the following formula of y = mx + b
m = slope, it is the coefficient of X
y = 4/5 X - 3
m = 4/5
The possible outcomes for 1 HEAD and 3 TAILS are
HTTT
THTT
TTHT
TTTH
Assuming the coin is a fair coin, we have:
Probability of tossing head is 0.5
Probability of tossing tail is 0.5
Probability of tossing the coin four times for each outcome combination listed above is
HTTT = 0.5×0.5×0.5×0.5 = 0.0625
THTT = 0.5×0.5×0.5×0.5 = 0.0625
TTHT = 0.5×0.5×0.5×0.5 = 0.0625
TTTH = 0.5×0.5×0.5×0.5 = 0.0625
Hence, probability of getting three tails and one head from 4 tossing is
4×0.0625 = 0.25
He will get 12 issues too. Since he spent 15 dollars in total you would divide that by 1.50 to see how many he actually purchased and it comes out to 10 meaning that he got 10 issues with the money. Now he got two free issues so you would add them to the ones he purchased, so 10 + 2 which would equal 12. So in total he got 12 issues. I hope that helps and wasn't confusing.