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brilliants [131]
2 years ago
10

Last question I need i have gotten everything else please help me if you can​

Mathematics
2 answers:
snow_lady [41]2 years ago
5 0
It’s 64 guys come on make me brainlist
Goryan [66]2 years ago
3 0

Answer:

There are 39 people in the Filmmaking club and 25 in the Yearbook Club

X = 39

39x + 25y = 64

Step-by-step explanation:

I really hope this is right, it was kinda confusing! Sorry if I got it wrong!!

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Find the least common denominator (LCD)11/6 and 4/9.
viva [34]

Answer: 18

Step-by-step explanation:

11/6 * 3/3 = 33/18

4/9 * 2/2 = 8/18

Hope this helps! Please give brainliest :)

5 0
2 years ago
8/9 with a exponet of 0
svetoff [14.1K]

Answer:

1

Step-by-step explanation:

this is because the number is not getting multiplied by anything.

3 0
3 years ago
Read 2 more answers
8x+112x+392 factor perfect squares
Elis [28]

1

2

0

x

+

120x+392

Step-by-step explanation:

4 0
3 years ago
Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
erica [24]
<h2>Answer:</h2>

\frac{2}{x}

\frac{x}{2}

\frac{4x^4}{y^3}

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

2x^4 . \frac{1}{4x^3}

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

Therefore, 2x⁴ . 4x⁻³ = \frac{x}{2}

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

8 0
3 years ago
-6z+(-5.5)+3.5z+5y-2.5 simplyfied?
frosja888 [35]

Answer:

  • \boxed{\sf -2.5z+5y-8}

Step-by-step explanation:

\sf -6z+(-5.5)+3.5z+5y-2.5

\sf -6z-5.5+3.5z+5y-2.5

\sf -6z+3.5z+5y-5.5-2.5

\sf( -6z+3.5z) \sf (5y) \sf (-5.5-2.5)

\sf -2.5z+5y-8

\underline{--------------}

Hope it helps! :)

3 0
2 years ago
Read 2 more answers
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