<h3>To find the product of 42.12 and 10^3, move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>
<em><u>Solution:</u></em>
Given that,

Which means,

Here, the exponent of 10 is positive ( which is 3)
When the exponent is positive, we have to move the decimal point to right
When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10
Here, exponent is 3 , therefore move the decimal point right 3 places in 42.12
Therefore,

This question is Incomplete
Complete Question
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)
Answer:
0.7762
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Population mean = 6.20 bl/s
Standard deviation = 1.58 bl/s.
x = 5 bl/s
z = 5 - 6.20/1.58
z = -0.75949
The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)
Probability value from Z-Table:
P(x<5) = 0.22378
P(x>5) = 1 - P(x<5)
= 1 - 22378
= 0.77622
Approximately to 4 decimal places = 0.7762
The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762
93.96. You multiply them together to get the answer.
In this question, we have to use the intersecting chord theorem, and the formula which is

In the given circle, values of AP, CP and DP are 12m, 6m and 5m respectively .
Substituting the values in the formula, we will get

Dividing both sides by 5

we will draw the graph according to the given constraints
NOTE: when we draw the graph from constraints inequalities becomes equalities just to draw the graph
Given constraints are:




Now we draw the graph of given constraints using graphing calculator. Please see the attachment for the graph. Shaded region is the feasible region