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Serhud [2]
3 years ago
13

Work out the answers to the following:

Mathematics
1 answer:
salantis [7]3 years ago
7 0

Step-by-step explanation:

a)9000

b)40

c)6300

d)125

I hope it's helpful!!

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adell [148]
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5 0
3 years ago
I Prove that Cos(90-θ)/1+sin(90-θ) +1+sin(90-θ) /cos(90-θ) =2
USPshnik [31]
Okay,

so first you gotta know that cos(90-x) is equal to sinx and sin(90-x) is equal to cosx!!
Now all you gotta do is replace the cos(90-x) to sinx in the numerator and sin(90-x) to cosx in the denomenator inorder to make the numerator all into sin and denomenator all into cos.
After that, open up the brackets and solve...
At the end you'll hopefully get something like this :( 1+sin90 ÷ 1+cos90 )
And since sin90 is 1 (put it in the calculator!) and cos90 is 0, you'll get 2÷1 which is equals to 2!!

Hope this helped!  :)
6 0
3 years ago
Read 2 more answers
Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29
hram777 [196]

Answer:

\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }

Step-by-step explanation:

Hello,

I assume that we are working in \mathbb{C}, otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

   p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

So

\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }

Now, we need to find the zeroes of the second factor, meaning finding x so that:

x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4}  \\ \\  x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\  x = 2+5i \ \text{ or } \ x = 2-5i

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
In 1995, Derek Jeter's batting average was 0.250; in 1996, his batting average was 0.314. David Justice's batting average in 199
belka [17]

Answer:

The correct option is;

Simpson Paradox

Step-by-step explanation:

The phenomenon whereby particular trends are prevalent in small data portions but are not evident or an inverse trend is observe when the portions are joined together is known as Simpson's paradox.

Whereby the data for calculating the bating averages as found online are given as follows;

Season,                       Derek Jeter                           David Justice

1995,                           12/48 = 0.250                         104/411 ≈ 0.253

1996,                           183/582 ≈ 0.314                      45/140 ≈ 0.321

The overall hits to the overall bats ratio are;

,         (183 + 12)/(582 + 48) ≈0.310   (104+45)/(411+140) = 0.27

Which shows that  Derek Jeter's overall average was better than Justice's average  

7 0
3 years ago
What +1/16 = 3/2 answer please
Law Incorporation [45]

Answer:

1   7/16

Step-by-step explanation:

5 0
2 years ago
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