Step-by-step answer:
Please refer to attached image.
1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning
that
angles QPS and QRS are supplementary =>
QPS+QRS=180 =>
QRS = 180 - 74 = 106
2. Triangle RSQ is isosceles with RS=RQ =>
angles RSQ and RQS are congruent.
3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37
4. QP is a diameter => angle QSP is a right-angle.
5. From (3) and (4) above,
angle RSP = 37+90 = 127
6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>
RQP+RSP = 180 =>
x + 127 = 180 =>
x = 180 - 127 = 53 degrees.
The distance from third base to first base is 127.3 feet.
Answer:
-1/1
Step-by-step explanation:
Is the another way to simplified, there's no other way besides that and 121.
Answer:
In y = mx + b , the slope is "m", which is multiplied by x, and "b" is the y-intercept
Step-by-step explanation:
Answer:
256
Step-by-step explanation:
since the the path surounds both sides of the garden you have to add 2 x instead of just x
let me show you what i mean. 10=garden width and 3=path width=x
since it is a square, we can calculate the area by taking one side and squaring it so you get (10+2x)^2 which is 16^2 since x is 3, the width of the garden
to do simaler problems just use thei formula (garden length+2path length)^2 or (garden length+2path length)times(garden length+2path length)