Given:
s is inversely proportional to t.
When s = 0.5, t = 7.
To find:
The value of s when t=0.8.
Solution:
s is inversely proportional to t.
...(i)
Where, k is the constant of proportionality.
Putting s=0.5 and t=7, we get
Putting k=3.5 in (i), we get
This is the equation of proportionality.
Putting t=0.8, we get
Therefore, the value of s is 4.375 when t=0.8.
Answer:
im not the best at algebra but
2a+3b+4c
Step-by-step explanation:
subtract
(2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
add
=(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
then subtract
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
Answer:
16.02
Step-by-step explanation:
2. What inference can you make by comparing the measures
of variability?
I need the answer
16.02
The missing length is 51.5, I hope this helps :)
