What is 4 (1/2+ 5/4) + -5=
1 answer:
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(C) fraction of the marbles now in the bag is blue.
- A fraction is a portion of a whole or, more broadly, any number of equal parts.
- In everyday English, a fraction represents the number of pieces of a specific size, such as one-half, eight-fifths, or three-quarters.
- A common, vulgar, or simple fraction that consists of a numerator above a line and a non-zero denominator below that line.
- Numerators and denominators are also employed in uncommon fractions such as compound fractions, complex fractions, and mixed numerals.
To find what fraction of the marbles now in the bag is blue:
- Important information is that immediately before the last step blue marbles formed
from the marble in the bag.
- That means that there were
blue and
other marbles, for some
- When we double the number of blue marbles, there will be
blue and
- Hence, blue marbles now form
all marbles in the bag.
Therefore, (C) fraction of the marbles now in the bag is blue.
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Complete question:
A bag initially contains red marbles and blue marbles only, with more blue than red. Red marbles are added to the bag until only 1 / 3 of the marbles in the bag are blue. Then yellow marbles are added to the bag until only 1 / 5 of the marbles in the bag are blue. Finally, the number of blue marbles in the bag is doubled. What fraction of the marbles now in the bag are blue?
(A) 1/5
(B) 1/4
(C) 1/3
(D) 2/5
(E) 1/2
The maximum height of the rocket is 43.89 feet
<h3>How to write the function</h3>The general function is given as:
h(t) = -16t^2 + vt + h
The initial velocity is
v = 53
So, we have:
h(t) = -16t^2 + 53t + h
The initial height is
h = 0
So, we have:
h(t) = -16t^2 + 53t
Hence, the function of the height is h(t) = -16t^2 + 53t
<h3>The maximum height of the rocket</h3>
In (a), we have:
h(t) = -16t^2 + 53t
Differentiate the function
h'(t) = -32t + 53
Set to 0
-32t + 53 = 0
This gives
-32t = -53
Divide by -32
t = 1.65625
Substitute t = 1.65625 in h(t) = -16t^2 + 53t
h(1.65625) = -16 * 1.65625^2 + 53 * 1.65625
Evaluate
h(1.65625) = 43.890625
Approximate
h(1.65625) = 43.89
Hence, the maximum height of the rocket is 43.89 feet
<h3>Time to hit the ground</h3>In (a), we have
h(t) = -16t^2 + 53t
Set to 0
-16t^2 + 53t = 0
Divide through by -t
16t - 53 = 0
Add 53 to both sides
16t = 53
Divide by 16
t = 3.3125
Hence, the time to hit the ground is 3.3125 seconds
<h3>The graph of the function h(t)</h3>See attachment for the graph of the function h(t)
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