Question

1. is he equation true , false, or open

Answer 1

Question 1:

For this case we have the following equation:

 $5x ^ 2 = 6x + 11$

We observe that the equation is a polynomial of the second degree.

Therefore, the equation has two possible solutions.

The variable of the equation for this case is x.

In this case, we have an open equation because we have a variable.

Rewriting the equation we have:

$5x ^ 2 - 6x - 11 = 0$

Answer:

open, there is a variable.

Question 2:

For this case we have the following equation:

 $2-8x = -6$

From here, we must clear the value of x.

For this, we follow the following steps:

1) Pass the value of 8x adding:

$2 = -6 + 8x$

2) Pass the value of 6 adding:

$2 + 6 = 8x$

3) Add the values ​​on the same side of equality:

 $8x = 8$

4) Pass the 8 to divide:

$x = \frac{8}{8} = 1$

Answer:

The value of x is given by:

$x = 1$

Question 3:

For this case we have the following equation:

 $y = x-4$

The ordered pair solution is the one that satisfies both sides of the equation.

For the point (6, 2) we have:

$x = 6 y = 2$

Substituting values ​​we have:

$2 = 6-4 2 = 2$

We observe that both sides of the equation are equal.

Therefore, the ordered pair solution is (6, 2)

Answer:

An ordered pair that is a solution of the equation y = x-4 is:

(6, 2)

Answer 2

1. is he equation true , false, or open5x 2=6x 11 
open, there is a variable

which value is a solution of the equation 2-8x= -6 
x = 1

which ordered pair is a solution of the equation y=x-4 
 (x,y) = (6,2)