Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula.
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C.
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space.
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.
Answer:
Figure G.
Step-by-step explanation:
Let's check through the values and calculate the radius and area for all the circle.
For circle R
Diameter = 2 feet
Radius= 1 feet
Area= πr²
Area= 3.14*1
Area= 3.14 feet²
CircleS
Diameter= 4 feet
Radius= 2 feet
Area= πr²
Area= 3.14*2²
Area= 12.56 feet²
Circle T
Diameter= 8 feet
Radius= 4 feet
Area = π r²
area= 3.14*4²
Area=50.24 feet²
Circle U
Diameter= 12 feet
Radius= 6 feet
Area = π r²
area= 3.14*6²
Area=113.04 feet²
The values of the radius and Area all match the graph in figure G
Answer:
Events E and F are independent.
Step-by-step explanation:
E = {multiple of 3} = {3, 6, 9, 12}
P(E) = 4/12
F = {even number} = {2, 4, 6, 8. 10, 12}
P(F) = 6/12
E and F = {even and multiple of 3} = {6, 12}
P(E∩F) = 2/12
In order for two events to be independent the following relationship must be true:
Testing this property:
The relationship holds true, thus events E and F are independent.
Answer:
(7,-9)
Step-by-step explanation:
Answer:
30 cards
Step-by-step explanation:
