All categories

3 years ago

PLEASE HELP !!! ITS A TEST (problem is included in picture :))

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

5 0

Answer:

(-4, -8)

Step-by-step explanation:

NikAS [45]3 years ago

4 0

Answer:

(-4,-8)

thats the anwser I think I just did the work so ya

You might be interested in

The cooper family owns a luxury sedan and a compact car. The fuel tank capacity of the luxury sedan 9s 22.45 gallons and that of

Viefleur [7K]

Answer:

$13.75\ gal$

Step-by-step explanation:

we know that

To find out the difference In the fuel tank of the two cars, subtract the fuel tank capacity of the compact car from the fuel tank capacity of the luxury sedan

$22.45-8.7=13.75\ gal$

4 0

3 years ago

a gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sel

adell [148]

Answer:

The price per wind chime that will maximize revenue = $ 315

Step-by-step explanation:

Given - A gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sell 5 fewer wind chimes per month.

To find - Find the price per wind chime that will maximize revenue.

Proof -

Given that,

Total Wind chimes selling = 160

Price of each Wind chime = $150

Now,

Given that, for each $15 increase in price, they will sell 5 fewer wind chimes per month.

So,

Let the price = 150 + 15x

So,

Number of wind Chimes sold per month = 160 - 5x

So,

Total Revenue, R = (150 + 15x)(160 - 5x)

= 24000 - 750x + 2400x - 75x²

= 24000 + 1650x - 75x²

⇒R(x) = 24000 + 1650x - 75x²

Differentiate R with respect to x , we get

R'(x) = 1650 - 150x

Now,

For Maximize Revenue, Put R'(x) = 0

⇒1650 - 150x = 0

⇒150x = 1650

⇒x = 1650/150

⇒x = 11

∴ we get

Price per Wind chime = $ 150 + 15(11)

= $ 150 + 165

= $ 315

So,

The price per wind chime that will maximize revenue = $ 315

3 0

3 years ago

A recent study asked U. S. Adults to name 10 historic events that occurred during their lifetime that have had the greatest impa

Nadusha1986 [10]

Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, the parameters are:

$z = 2.575, n = 2000, \pi = 0.77$

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7458$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7942$

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

More can be learned about the z-distribution at brainly.com/question/25890103

7 0

2 years ago

Marvin marked off the ground for a rectangular garden. The garden was to have an area represented by the polynomial expression 2

mafiozo [28]

Answer: 621

Step-by-step explanation: 28^2+ 13 − 176

length, width, and height.

8 0

2 years ago

I NEED HELP!! ASAP PLEASE!!!

mariarad [96]

Answer:

Step-by-step explanation:

a:angles given do not necessarily prove that ADP and BCP is 30 they can be different

c:angles given are not in triangles

b:with regards to the square I don't think you can really prove the statement

5 0

3 years ago