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Murljashka [212]
3 years ago
15

Bakit mahalaga na marunong tayong gumamit ng makina?

Computers and Technology
1 answer:
jeka943 years ago
5 0

Answer:

para mabilis ang gawa

Explanation:

hope it helps

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In his article, “How to Publish Without Perishing,” what does James Gleick believe most people do when they really read a book?
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James Gleick believes that they immerse themselves in a rich textual world. The answer is C.

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Jason is the network manager and is leading a project to deploy a SAN. He is working with the vendor's support technician to pro
ikadub [295]

Answer:

Network diagrams.

Explanation:

In this scenario, Jason is the network manager and is leading a project to deploy a storage area network (SAN). He is working with the vendor's support technician to properly set up and configure the SAN on the network. To begin SAN input and output (I/O) optimization, Jason need to provide the network diagram to the vendor support technician.

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Basically, it gives an illustration of all the equipments such as routers, switches, hubs etc.

7 0
2 years ago
Which of these utility tools would you least expect a support agent to find useful to increase security for end users?
tia_tia [17]

Answer:

b. Network performance monitor

Explanation:

A utility tool can be defined as a software application or program designed to add more functionality to a computer system, as well as to improve its performance efficiently. Some examples of commonly used utility tools in computer are file and folder backup tools, file management, antivirus, hard disk diagnostics, registry cleaner, network performance monitor, screensavers etc.

In the context of increasing security for the end users, the most important utility tools are;

1. Antivirus utility: to scan, detect, remove and prevent computer viruses such as Malware, Trojan horses, keyloggers, botnets, adwares etc.

2. Rootkit utility: it can be used to detect and remove any rootkit program that is hidden in a computer.

3. Spyware utility: this is used to detect, remove and prevent malicious adware that are found in software applications.

<em>However, a network performance monitor is a utility tool that would be found to least support an agent in increasing security for end users because it is a utility tool that is primarily used to monitor network traffic and amount of data usage. </em>

7 0
3 years ago
Write a C++ program that reads from the standard input and counts the number of times each word is seen. A word is a number of n
Rufina [12.5K]

Answer:

#include <stdio.h>

#include <string.h>

#include <ctype.h>

 

struct detail

{

   char word[20];

   int freq;

};

 

int update(struct detail [], const char [], int);

 

int main()

{

   struct detail s[10];

   char string[100], unit[20], c;

   int i = 0, freq = 0, j = 0, count = 0, num = 0;

 

   for (i = 0; i < 10; i++)

   {

      s[i].freq = 0;

   }

   printf("Enter string: ");

   i = 0;

   do

   {

       fflush(stdin);

       c = getchar();

       string[i++] = c;

 

   } while (c != '\n');

   string[i - 1] = '\0';

   printf("The string entered is: %s\n", string);

   for (i = 0; i < strlen(string); i++)

   {

       while (i < strlen(string) && string[i] != ' ' && isalnum(string[i]))

       {

           unit[j++] = string[i++];

       }

       if (j != 0)

       {

           unit[j] = '\0';

           count = update(s, unit, count);

           j = 0;

       }

   }

 

   printf("*****************\nWord\tFrequency\n*****************\n");

   for (i = 0; i < count; i++)

   {

       printf("%s\t   %d\n", s[i].word, s[i].freq);

       if (s[i].freq > 1)

       {

           num++;

       }

   }

   printf("The number of repeated words are %d.\n", num);

 

   return 0;

}

 

int update(struct detail s[], const char unit[], int count)

{

   int i;

 

   for (i = 0; i < count; i++)

   {

       if (strcmp(s[i].word, unit) == 0)

       {

           s[i].freq++;

 

           return count;

       }

   }

   /*If control reaches here, it means no match found in struct*/

   strcpy(s[count].word, unit);

   s[count].freq++;

 

   /*count represents the number of fields updated in array s*/

   return (count + 1);

}

4 0
3 years ago
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