The energy of 632 is1.963ev
λ= 632.8nm=632×10⁻⁹ m
Power, P=9.42mW=9.42×10 ⁻³W
Energy of each photon in the light beam,
E= (hc)/λ =
(6.6×10 ⁻³⁴×3×10 ⁸) / 632.8×10⁻¹⁹ = 3.14×10 ⁻¹⁹ = (3.14×10 ⁻¹⁹)/1.6 x 10⁻¹⁹
= 1.963ev
The momentum of each photon in the light beam,
p = h/λ = (6.6×10 ⁻³⁴)/(632×10⁻⁹ ) = 1.046×10⁻²⁷ kgms⁻¹
Momentum is a measurement of mass in motion: how much mass is in how much motion. It is usually given the symbol p. Where m is the mass and v is the velocity.
Example - Whenever you toss a ball at someone as well as it smacks him square in the face. It indicates how difficult it would have been to stop the thing. A baseball is swooping through the air. A large truck is moving. A bullet discharged from such a firearm.
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Answer:
Q = 40.1 degrees
Explanation:
Given:
- The weight of the timber W = 670 N
- Water surface level from pivot y = 2.1 m
- The specific density of water Y = 9810 N / m^3
- Dimension of timber = (0.15 x 0.15 x 0.0036) m
Find:
- The angle of inclination Q that the timber makes with the horizontal.
Solution:
- Calculate the Flamboyant Force F_b acting upwards at a distance x along the timber, which is unknown:
F_b = Y * V_timber
F_b = 9810*0.15*0.15*x
F_b = 226.7*x N
- Take static equilibrium conditions for the timber, and take moments about the pivot:
(M)_p = 0
W*0.5*3.6*cos(Q) - x/2 * F_b*cos(Q) = 0
- Plug values in:
670*0.5*3.6 - x^2 * 0.5*226.7 = 0
x^2 = 1206 / 113.35
x = 3.26 m
- Now use the value of x and vertical height y to compute the angle of inclination to be:
sin(Q) = y / x
sin(Q) = 2.1 / 3.26
Q = sin^-1 (0.6441718)
Q = 40.1 degrees
The answer would be 21.6 but rounded up it would be 22J.
H = mc∆T
where, H=heat energy
c = SHC
H = 2*921*(40-20)
H = 36840J
H = 36.84KJ
The energy transferred to it is 36.84KJ
Answer:
47
Explanation:
48km:1hr (10sec×60min=600hr)
¥ :600hr
1hr÷¥=1. 48×600÷1=2800
2800÷60=47
47 will be the acceleration