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Butoxors [25]
2 years ago
10

.

Physics
2 answers:
Lerok [7]2 years ago
5 0

Answer:

47

Explanation:

48km:1hr (10sec×60min=600hr)

¥ :600hr

1hr÷¥=1. 48×600÷1=2800

2800÷60=47

47 will be the acceleration

Leni [432]2 years ago
3 0

\text{Initial velocity,}~ u = 0 ~ ms^{-1}\\\\\text{Final velocity,}~ v = 48~kmh^{-1} = \dfrac{48\times 1000}{3600} ms^{-1} = 13.33 ms^{-1}\\ \\\text{Time,}~ t = 10~ sec\\\\\text{Acceleration,}~ a = \dfrac{v-u}{t} = \dfrac{13.33-0}{10} = \dfrac{13.33}{10} = 1.33 ~ ms^{-2}\\\\\text{Hence the acceleration of the car is}~ 1.33 ~ms^{-2}.

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5 0
3 years ago
Read 2 more answers
what is the minimum (nonzero) thickness of the coating for which there is maximum transmission of the light into the rod?
timofeeve [1]

The thickness is 155 nm at t1.

The thickness is 77.3 nm at t2.

The inquiry informs us that the laser light's wavelength is λ=510nm

The plastic rod's refractive index is n=1.30

The transparent coating's refractive index is nr=1.65

Minimum reflection would be required for maximal light transmission into the rod, and it is mathematically described as

2t1=510+10⁻⁹/1.65

t1=510+10⁻⁹/1.65*2

t1=155nm

where m is the interference order, which equals 1.

2t2= {m+1/2} λ/nr

The thickness is t replacing values

t1=155 nm

The highest reflection would occur for minimal light penetration through the rod, and this maximum reflection is mathematically described as

2t2= [m+1/2] λ/nr

t2=77.3 nm

The complete question is- Laser light of wavelength 510 nm is traveling in air and shines at normal incidence onto the flat end of a transparent plastic rod that has n = 1.30. The end of the rod has a thin coating of a transparent material that has refractive index 1.65. What is the minimum (nonzero) thickness of the coating (a) for which there is maximum transmission of the light into the rod; (b) for which transmission into the rod is minimized?

Learn more about reflection here-

brainly.com/question/15487308

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