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elena-s [515]
3 years ago
10

1/3x plus 3/4 plus 2/3x -1/4-2/3x please help :(

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

Answer:

1/3 x  + 1/2

Step-by-step explanation:

combine like terms   the two opposites cancel out  2/3 and -2/3

1/3x + 3/4 -1/4            3/4 -14 = 12

13x + 1/2  (answer)

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Step-by-step explanation:

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2 years ago
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Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
I’m A Triangle, The Sum Of Any Two Side Lenghts, <br><br> Finish The Sentence
Alchen [17]
Equals the third side length
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3 years ago
A savings account is started with an initial deposit of $700. The account earns 1.5% interest compounded
marusya05 [52]

Answer:

  (a)  A = 700×1.015^t

  (b)  36.2 years

Step-by-step explanation:

(a) Each year, the account value is multiplied by (1 + 1.5%) = 1.015. Repeated multiplication is signified using an exponent. In t years, when the account has been multiplied by 1.015 t times, the account value will be ...

  A = $700×1.015^t

__

(b) You want to find t when A=$1200. Logarithms are involved.

  1200 = 700×1.015^t . . . . use 1200 for A

  1200/700 = 1.015^t . . . . . divide by 700

  log(12/7) = t×log(1.015) . . . . . take logarithms

  log(12/7)/log(1.015) = t ≈ 36.2 . . . . divide by the coefficient of t

It will take about 36.2 years for the account balance to reach $1200.

4 0
3 years ago
A. -24<br> B. -20<br> C. -5<br> D. -4
Ivahew [28]
I believe your answer is C
6 0
3 years ago
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