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aleksklad [387]
2 years ago
15

Triangle Proofs Please help

Mathematics
1 answer:
oksian1 [2.3K]2 years ago
4 0

Explanation:

There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.

<u>Statement</u> . . . . <u>Reason</u>

2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle

3. AD ≅ BD

and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle

4. ∠CAE = ∠CAD +∠DAE

and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate

5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality

6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality

7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality

8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate

9. ∠ACD ≅ ∠BCD . . . . CPCTC

10. DC bisects ∠ACB . . . . definition of angle bisector

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so lets look at DE...it is 2.....and D'E' is 6

so 2 * x = 6...with ur scale factor being x
2x = 6
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Answer all for brainliest
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Step-by-step explanation:

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A multiple choice test is composed of 10 questions. Each question has four possible answers, only one of the four possible answe
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Answer:

Let X the random variable of interest "Number of correct anwers on the tet", on this case we now that:

X \sim Binom(n=10, p=0.25)

And the expected value is given by:

E(X) = np =10*0.25 = 2.5

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Let X the random variable of interest "Number of correct anwers on the tet", on this case we now that:

X \sim Binom(n=10, p=0.25)

And the expected value is given by:

E(X) = np =10*0.25 = 2.5

4 0
3 years ago
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