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Mathematics

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agasfer [191]3 years ago

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this is good looking nice photo but li can't give you answer of that sorry.

Step-by-step e this https://www.commonlit.org/en/students/student_lesson_activities

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Sienna used the scale drawing above to create a pool that is 14 ft wide x 22 ft long. She then decided to make pool with a final

Bond [772]

A scale factor allows a shape to be changes into another shape by changing the linear dimensions to the multiples of the initial dimension and a constant

The expression that finds the change in scale factor for the longer pool with a final length of 33 ft. Sierra is building is the option;

$\dfrac{2 \, ft.}{3 \, ft.}$

Reason:

Known parameters are;

Dimensions of the pool created = 14 ft. wide × 22 ft. long

Final length of the pool = 33 ft.

Let <em>x</em> represent the length of the drawing using the initial scale factor, we have;

$The \ initial \ scale \ factor = \dfrac{22 \, ft.}{x \, in.}$

The scale factor of the drawing following a final length of 33 ft. is therefore;

$New \ scale \ factor = \dfrac{33 \, ft.}{x \, in.}$

The change in scale factor is given as follows;

$Change \ in \ scale \ factor = \dfrac{Initial \, scale \, factor}{Final \, scale \, factor}$

Therefore;

$Change \ in \ scale \ factor = \frac{\left( \dfrac{22 \, ft.}{x \, in.} \right)}{\left( \dfrac{33 \, ft.}{x \, in.} \right)} = \dfrac{2 \, ft.}{3 \, ft.}$