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2 years ago

Find the area of the figure. Use 3.14 for pie . Round your answer to the nearest tenth.

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

7 0

Answer:

538.3

Step-by-step explanation:

First of all find the area of the rectangle

L*W

15*30

450

Now find the area of semi circle

1/2 $\pi r^{2}$

Since radius is half a diameter divided 15 by 2=7.5

1/2 $\pi 7.5^{2}$ 7.5 times 7.5= 56.25

1/2*3.14*56.25

56 times 3.14 is 176.625 now multiply 176.625 by 1/2

Answer is 88.3125

Now add 450 to 88.3125

Final answer: 538.3125

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What is the perimeter of rhombus LMNO? 20 units 24 units 40 units 48 units

NeTakaya

The little lines on each side of the rhombus mean that all the sides are the same length.

We can set line LM and MN equal to solve for X, then we can solve the length of a side.

3x-3 = x+7

Add 3 to each side:
3x = x +10

Subtract x from each side:

2x = 10

Divide both sides by 2:
x = 10/2
x = 5

Now we have the value for x, replace x in one of the side formulas:

x +7 = 5+7 = 12

Each side = 12 units.

The perimeter would be 12 + 12 + 12 + 12 = 48 units.

3 0

2 years ago

Read 2 more answers

The perimeter of a square is 36<br>what is the area of the square?

zmey [24]

Answer: 81 units²

Step-by-step explanation: To solve this problem, remember that the formula for the area of a square is 4s.

Therefore, since the perimeter of the given square is 36, we have 36 = 4s and dividing both sides by 4, 9 = s.

Now, remember that the formula for the area of a square is s² and since the length of a side of the given square is 9, we have (9)² or 81.

So the area of a square that has a perimeter of 36 is 81 units².

6 0

2 years ago

A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form

Over [174]

Answer:

$\vec{v}= \text{ or } \approx$

Step-by-step explanation:

Component form of a vector is given by $\vec{v}=$ , where $i$ represents change in x-value and $j$ represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector $\vec{v}=$ , the magnitude is $||v||=\sqrt{i^2+j^2$ .

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being $i$ , one leg being $j$ , and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

$\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}$

To find the other leg, $i$ , we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

$\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}$