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IrinaVladis [17]
3 years ago
8

I’m not very smart at math can anyone answer this?

Mathematics
1 answer:
Tresset [83]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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What’s this answer ????????
Paraphin [41]

2= f/8

Mutiply both sides by 8

(2/(8)= 16

f/8(8)= f ( crossed out 8 and 8)

Answer: f= 16

3 0
3 years ago
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What is the range of the function?<br> The function f(x) = -(x + 5)(x + 1) is shown.
Anton [14]

Answer:

Step-by-step explanation:

u do 5 times x then do 1 times f .

6 0
3 years ago
Aisha wants to paint the four walls of her living room. Each wall is 2.6 m high and 3.5 m long. One wall has a door of 2.2 m by
Snowcat [4.5K]

Answer:

£22

Step-by-step explanation:

Area to be painted

4walls - door

a = 4(2.6 * 3.5) - 2.2 * 0.8

a = 34.64 m²

Paint needed

p = 34.64 / 8

p = 4.33

Must round up

p = 5 liters

Tins needed

t = 5/2

t = 2.5

must round up

t = 3

Cost

since 1 is free with 2 will pay for 2

c = 11 * 2

c = 22

£22

8 0
3 years ago
What are the terms in the expression 7x + 4y + 1?
Sphinxa [80]
There are 3 terms : 7x , 4y, and 1.
a term is separated by any math symbol
examples are =, +, *
7 0
4 years ago
Read 2 more answers
A farmer wants to fence a rectangular area of 72 square feet next to a river. Find the length and width of the rectangle which u
Arlecino [84]

Answer:

  • 12 ft parallel to the river
  • 6 ft perpendicular to the river

Step-by-step explanation:

The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.

72 = W(2W)

36 = W²

6 = W . . . . . . the width perpendicular to the river

12 = 2W . . . .  the length parallel to the river

_____

<em>Development of this relation</em>

Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...

  A = xy = x(T -x)/2

Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...

 x = (0 +T)/2 = T/2

The corresponding area width (y) is ...

  y = (T -T/2)/2 = T/4

Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.

8 0
3 years ago
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