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2 years ago

Solve the following system of equations: y=x+4 2x+y=13

Mathematics

2 answers:

const2013 [10]2 years ago

4 0

Substitute y from the first equation into the second:

2x+(x+4)=13
3x+4=13
3x=9
x=3.

Mazyrski [523]2 years ago

3 0

Okay, for this one is will use substitution:
y=x+4
y-x=4
2y-2x=8

-2x+2y=8
+
2x+y=13
=
3y=21
y=7
x=3 is your final answer. Hope it help!

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Read 2 more answers

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lozanna [386]

Standard equation of a circle: (x-h)² + (y-k)² = r² where (h, k) is the center and r is the radius. In the case of our equation here, (x-5)² + (y+3)² = 25, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = $\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Distance = $\sqrt{(-3-3)^2+(5-2)^2}$

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