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Ostrovityanka [42]
3 years ago
15

Geometry homework I need help pls pls pls

Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

vertex of 4 is 2

Step-by-step explanation:

cuh cuh uchuch uch uch uch

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Jasmine recorded the number of minutes she spent doing homework each day during the months of March and April.
larisa [96]

Answer:

5647

Step-by-step explanation:

You go to the store and get some chips to kill your dad

6 0
3 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
2 Kenedi has a piece of ribbon that measures
USPshnik [31]

Answer:

The length of each ribbon is 1.6 inches

Step-by-step explanation:

From the question, we are told that:

Kenedi has a piece of ribbon that measures 24 inches long. She cuts the ribbon into 15 equal pieces to attach to her dance costume

Hence, the expression that can be used to show how to calculate the length of each piece of ribbon is given as:

24 inches ÷ 15 pieces

= 24 ÷ 15

= 1.6 inches

Therefore, the length of each ribbon is 1.6 inches

4 0
3 years ago
What is the answer to this
tatiyna
The answer is= 2 6/10
3 0
4 years ago
The cost of a newsletter subscription is $20 per year. The cost is expected to increase 10% each year. Which expression can be u
a_sh-v [17]
Selection A is appropriate.

_____
20*1.1^n is the general expression for the cost n years in the future.
20*1.1^3 = 26.62 is the cost 3 years in the future.
4 0
3 years ago
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