Question

What are the solutions of x² + 6x - 6 = 10?

Answer 1

Answer: x=- 8 or x=2

Step-by-step explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

2. The quadratic  equation is:

$x^{2}+6x-6-10=0\\x^{2}+6x-16=0$

3. Then:

a=1

b=6

c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

$x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}$

$x_1=-8\\x_2=2$

Answer 2

Answer:

x = -8 or x = 2

Step-by-Step Explanation:

Given equation is :

x²+6x-6 = 10

Adding -10 to both sides of above equation,we get

x²+6x-6-10 = -10+10

x²+6x-16 = 0

We can solve above equation by factoring.

Split the middle term of above equation so that the sum of two terms should be 6 and their product be -16.

x²+8x-2x-16 = 0

Make two groups and taking common  

x(x+8)-2(x+8) = 0

Taking (x+8) common,we get

(x+8)(x-2) = 0

Applying zero-Product Property to above equation,we get

x+8 = 0 or x-2 = 0

x = -8 or x = 2 which is the answer.