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Fynjy0 [20]
3 years ago
10

Steve and carol live 405 miles apart, they start at the same time and travel toward each other, Steve speed is 6mph greater than

carols. If they meet in 2.5 hours, find their speed
Mathematics
1 answer:
babymother [125]3 years ago
6 0

Answer:

Speed of Carol is 78 mph and that of Steve is 84 mph.

Step-by-step explanation:

Let the speed of Carol is x mph and that of Steve is (x + 6) mph.

If they move towards each other with that speed, then the resultant speed will be (x + x + 6) = (2x + 6) mph

With this resultant speed, they cover 405 miles in 2.5 hours.

So, 2x + 6 = \frac{405}{2.5} = 162

⇒ 2x = 156

⇒ x = 78 mph

So, speed of Carol is 78 mph and that of Steve is (78 + 6) = 84 mph. (Answer)

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Answer:

The amount of more money than Antonia that Cal will have in his account after 12 months is $100

Step-by-step explanation:

The given parameters are;

The amount Antonia currently has in her savings account, P₁ = $4,500

The amount Antonia saves per month, S₁ = $150

The amount Cal currently has in his savings account, P₂ = $3,400

The amount Cal saves per month, S₂ = $250

Let the

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A₁ = P₁ + 12 × S₁

∴ A₁ = $4,500 + 12 × $150 = $6,300

Similarly, the amount, 'A₂', Cal has in 12 months is found as follows;

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The amount of money than Antonia that Cal will have after 12 months, 'A₂₋₁', is given as follows;

A₂₋₁ = A₂ - A₁ = $6,400 - $6,300 = $100.

The amount of money than Antonia that Cal will have after 12 months, A₂₋₁ = $100.

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