Standard form of 4 + 3y

Can someone please help me?

inna [77]

Answer:

25; 4; 1

Step-by-step explanation:

|------------| ( | |)-------------|

25% 25% ( 25% ) 25%

4 0

3 years ago

Read 2 more answers

Please help! Brainliest Answer! Thank You!

ziro4ka [17]

Answer:

B) 63°

Step-by-step explanation:

Step 1: find the angle beside x (inside the pentagon)

*A pentagon has a total of 540°

119 + 100 + 116 + 88 = 423

540 - 423 = 117

Step 2: x is a supplementary angle, which means it's angle adds up to 180°

Since we know the other angle is 117°, we just subtract that from 180

180 - 117 = 63

x = 63

5 0

3 years ago

Find the value of x help

Temka [501]

Answer:

6.7

Step-by-step explanation:

This is trigonometry. We will have to find the opposite leg and the hypotenuse is given to us as 10. So we will have to use sin.

Soh in Soh cah toa

So sin(42)=x/10

10 times sin(42)=x

Evaluate using a calculator=6.69130606 and so on

Rounded to the nearest tenth is 6.7

So the answer is 6.7

5 0

3 years ago

The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c

Anestetic [448]

Answer:

a) The mean is $\mu = 60$

b) The standard deviation is $\sigma = 9$

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when $X = 55.5, Z = -0.5$

So

$Z = \frac{X - \mu}{\sigma}$

$-0.5 = \frac{55.5 - \mu}{\sigma}$

$-0.5\sigma = 55.5 - \mu$

$\mu = 55.5 + 0.5\sigma$

The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when $X = 71.52, Z = 1.28$

So

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{71.52 - \mu}{\sigma}$

$1.28\sigma = 71.52 - \mu$

$\mu = 71.52 - 1.28\sigma$

Since we also have that $\mu = 55.5 + 0.5\sigma$

$55.5 + 0.5\sigma = 71.52 - 1.28\sigma$

$1.78\sigma = 71.52 - 55.5$

$\sigma = \frac{(71.52 - 55.5)}{1.78}$

$\sigma = 9$

$\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60$

Question

The mean is $\mu = 60$

The standard deviation is $\sigma = 9$

6 0

3 years ago

The weight of oranges growing in an orchard is normally distributed with a mean weight of 6.5 oz. and a standard deviation of 1.

sergey [27]

Add 3 standard deviations above and below the mean to get the range in which 99.7% of the data in a normal distribution will fall
6.5 + 4.5 = 11
6.5 - 4.5 = 2
So 2 to 11 ounces would be the interval

6 0

3 years ago

Standard form of 4 + 3y - 2x = 0​

Standard form of 4 + 3y - 2x = 0