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Airida [17]
3 years ago
9

Jasper withdrew $45.00 from her savings account. She then used her debit card to buy groceries for $30.15, and then deposited a

check for $14.65. What was the total amount of change in Jasper’s account?
Mathematics
2 answers:
hammer [34]3 years ago
8 0

Answer:

A money decrease of $60.50 (or -60.50 increase and change)

Step-by-step explanation:

? - 45 - 30.15 + 14.65 = -60.50

Since we are finding the change it is best to replace the question mark with 0 so that it is easier to solve.

0 - 45 = -45

-45 - 30.15 = -75.25

-75.25 + 14.65 = -60.50

alexandr1967 [171]3 years ago
5 0
The total amount of change in Jaspers account is 29.5
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Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is
Simora [160]
The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: A=s^2
Were 
A is the area in square kilometers 
s is one of the sides of the square
We know for our problem that  the side lengths of the field are 0.9 kilometers, so s=0.9. Lets replace that value in our formula to find A:
A=(0.9)^2
A=0.81 

Now, to find the population density of the filed, we are going to use the population density formula: P_{d}= \frac{I}{A}
where
P_{d} is the population density in <span>in burrows per square kilometer
</span>I is the number of burrows 
A is the are of the field
We know that I=1980 and A=0.81, so lets replace those values in our formula:
P_{d}= \frac{1980}{0.81}
P_{d}=2444.4

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5 0
3 years ago
Help asap will mark brainliest
katen-ka-za [31]

Answer:

(-5 3/4, 1 2/3)

Step-by-step explanation:

the line intersects right before the -6, so it’s not -6. yet, it is as close to -6 as you can get which would be -5 3/4. meaning the closes would be the third choice.

8 0
3 years ago
If p and q are a pair of supplementary angles , then p+q = ?​
ziro4ka [17]

Answer:

Step-by-step explanation:

Supplementary angles means that the angle sum of the two angles will equal 180 degrees :)

6 0
3 years ago
Read 2 more answers
In 2010, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephon
Zepler [3.9K]

<u>Answer</u>: No, we do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

Step-by-step explanation:

As per given , we have

H_0: \mu=9.4\\\\H_a:\mu\neq9.4, since H_0 is two-tailed so , the test is a two tail test.

Since population standard deviation is unknown, so we use t-test.

Critical value (two-tailed) for significance level of 0.01= t_{n-1,\alpha/2}=t_{49, 0.005}\pm2.609228

For n =50 , \overline{x}=8.6 and s= 4.8

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

t=\dfrac{8.6-9.4}{\dfrac{4.8}{\sqrt{50}}}\approx-1.18

Since test statistic value (-1.18) lies in critical interval (-2.609228, 2.609228), it means the null hypothesis is failed to reject.

We do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

4 0
3 years ago
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BlackZzzverrR [31]

Answer:

68% of plans cost between $62.16 and $86.52.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean: 74.34

Standard deviation: 12.18

Bell-shaped is the same as normally distributed.

Estimate the number of plans that cost between $62.16 and $86.52.

62.16 is one standard deviation below the mean.

86.52 is one standard deviation above the mean.

By the Empirical rule, 68% of the measures are within 1 standard deviation of the mean.

So

68% of plans cost between $62.16 and $86.52.

7 0
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