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yan [13]
3 years ago
12

Riko wants to find the distance between the points (−2, −3) and (2, −5). His work is shown. StartAbsoluteValue negative 3 EndAbs

oluteValue + StartAbsoluteValue negative 5 EndAbsoluteValue = 3 + 5 = 8. The distance is 8 units. Riko correct? Explain why or why not.
Mathematics
2 answers:
swat323 years ago
7 0

Answer:

<em>Riko is wrong because she uses the wrong formula.</em>

Step-by-step explanation:

Given the coordinate points (-2, -3) and (2, -5)

We are to find the distance between the two points

Using the formula:

D = √(x2-x1)²+(y2-y1)²

From the coordinates x1 = -2, y1 = -3, x2 = 2 and y2 = -5

Substitute

D = √(2-(-2))²+(-5-(-3))²

D= √(4)²+(-2)²

D = √16 + 4

D = √20

D = √4*√5

D = 2√5

<em>This shows that Riko is wrong because she uses the wrong formula.</em>

Stolb23 [73]3 years ago
7 0

Answer:Sample Response: No, Riko is not correct. The points do not have the same x-coordinates. If you connect the points, they do not form a horizontal or vertical line, so you cannot count spaces or use absolute value to find the distance.

Step-by-step explanation:

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A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
3 years ago
The 7th grade has 159 students. There are twice as many boys in the grade as there are girls.
aleksklad [387]

Answer:

106 boys

Step-by-step explanation:

7th grade = 159 students

Boys to girls ratio:

2:1

Find two thirds of 159:

2/3*159 = 106 boys

159-106= 53 girls

Check:

53*2 = 106

3 0
3 years ago
Read 2 more answers
Solve x^2 + 6x + 4=0?
kati45 [8]
You need to use the quadratic formula for this question.
\frac{-b+- \sqrt{b^2-4ac} }{2a}
In your equation, a is 1, b is 6, and c is 4. (I couldn't find a plus minus sign, so that's what the +- means, sorry if there's confusion.)
Sub those into the quadratic formula, and 
\frac{-6+- \sqrt{(6)^2-4(1)(4)} }{2(1)}
For the first answer, we should get 
x1=-0.7639, when you add the √6^2-4(1)(4)
For the second answer, we get
x2=-5.2361 when we subtract the √6^2-4(1)(4)
Therefore, the x values that make this equation equal to 0 should be approximately -0.7639 and -5.2361.
The more specific answers are
x1= -3+√5 and x2=-3-√5.

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3 years ago
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90 hours of training would you need to pay

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