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yan [13]
3 years ago
12

Riko wants to find the distance between the points (−2, −3) and (2, −5). His work is shown. StartAbsoluteValue negative 3 EndAbs

oluteValue + StartAbsoluteValue negative 5 EndAbsoluteValue = 3 + 5 = 8. The distance is 8 units. Riko correct? Explain why or why not.
Mathematics
2 answers:
swat323 years ago
7 0

Answer:

<em>Riko is wrong because she uses the wrong formula.</em>

Step-by-step explanation:

Given the coordinate points (-2, -3) and (2, -5)

We are to find the distance between the two points

Using the formula:

D = √(x2-x1)²+(y2-y1)²

From the coordinates x1 = -2, y1 = -3, x2 = 2 and y2 = -5

Substitute

D = √(2-(-2))²+(-5-(-3))²

D= √(4)²+(-2)²

D = √16 + 4

D = √20

D = √4*√5

D = 2√5

<em>This shows that Riko is wrong because she uses the wrong formula.</em>

Stolb23 [73]3 years ago
7 0

Answer:Sample Response: No, Riko is not correct. The points do not have the same x-coordinates. If you connect the points, they do not form a horizontal or vertical line, so you cannot count spaces or use absolute value to find the distance.

Step-by-step explanation:

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Heyo! I need some help, please. What is the x coordinate if (x, 17) is on a line that passes through the points (1, 2) and (-1,
expeople1 [14]

Answer:

  • x = 4

Step-by-step explanation:

<u>The line with points (1,2) and (-1,-8). Work out its equation.</u>

  • y = mx + b

<u>The slope is:</u>

  • m = (-8 - 2)/(-1 - 1) = -10/-2 = 5

<u>To find the y intercept, substitute x and y-xoordinates of point (1,2):</u>

  • 2 = 5(1) + b
  • b = 2 - 5
  • b = -3

<u>The line is:</u>

  • y = 5x - 3

<u>Point (x, 17), substitute y-coordinate and solve for x</u>

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  • 5x = 20
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5 0
3 years ago
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Find the center and radius of the circle 3 x squared plus 3 y squared plus 6 y equals 03x2+3y2+6y=0.
denis23 [38]

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The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion
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Find the slope of the line that passes through the points shown in the table.

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Step-by-step explanation:

8 0
2 years ago
If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?
bixtya [17]

Answer:

T_{2} = 200

Step-by-step explanation:

Given

Geometry Progression

T_1 = 500

T_4 = 32

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

T_n = ar^{n-1}

For first term: Tn = 500 and n = 1

500 = ar^{1-1}

500 = ar^{0}

500 = a

a = 500

For fought term: Tn = 32 and n = 4

32 = ar^{4-1}

32 = ar^3

Substitute 500 for a

32 = 500 * r^3

Make r^3 the subject

r^3 = \frac{32}{500}

r^3 = 0.064

Take cube roots

\sqrt[3]{r^3} = \sqrt[3]{0.064}

r  = \sqrt[3]{0.064}

r = 0.4

Using:  T_n = ar^{n-1}

n = 2     r = 0.4     and a = 500

T_{2} = 500 * 0.4^{2-1}

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T_{2} = 200

<em>Hence, the second term is 200</em>

5 0
3 years ago
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