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yan [13]
2 years ago
12

Riko wants to find the distance between the points (−2, −3) and (2, −5). His work is shown. StartAbsoluteValue negative 3 EndAbs

oluteValue + StartAbsoluteValue negative 5 EndAbsoluteValue = 3 + 5 = 8. The distance is 8 units. Riko correct? Explain why or why not.
Mathematics
2 answers:
swat322 years ago
7 0

Answer:

<em>Riko is wrong because she uses the wrong formula.</em>

Step-by-step explanation:

Given the coordinate points (-2, -3) and (2, -5)

We are to find the distance between the two points

Using the formula:

D = √(x2-x1)²+(y2-y1)²

From the coordinates x1 = -2, y1 = -3, x2 = 2 and y2 = -5

Substitute

D = √(2-(-2))²+(-5-(-3))²

D= √(4)²+(-2)²

D = √16 + 4

D = √20

D = √4*√5

D = 2√5

<em>This shows that Riko is wrong because she uses the wrong formula.</em>

Stolb23 [73]2 years ago
7 0

Answer:Sample Response: No, Riko is not correct. The points do not have the same x-coordinates. If you connect the points, they do not form a horizontal or vertical line, so you cannot count spaces or use absolute value to find the distance.

Step-by-step explanation:

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An object is dropped from a building and allowed to freefall to the ground. The height of the object over time is shown in the t
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Answer: The (magnitude of the) rate of change increases over time. The object drops 16 feet in the first second, but 80 feet in the last second.


Explanation:


1) I will start by showing the table in an easy way to read and understand:


Time (seconds)   Height (feet)

0                           144

1                            128

2                           80

3                             0


2) Rate of change


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  • The rate of change is calculated for every pair of consecutive points using this equation:

          rate of change = [change in height] / [time elapsed]


  • Calculations:

a) rate₁: [128 - 144] feet / [ 1 - 0] sec = - 16 feet / sec ⇒ the object drops 16 feet in the first second.


b) rate₂ = [80 - 128] feet / [2 - 1] sec = - 48 feet/sec ⇒ the object drops 48 feet in the next second


c) rate₃ = [0 - 80] feet / [3 - 2] sec = - 80 feet/sec ⇒ the object drops 80 feet in the last second.


The rate of change  is more negative every second: it increases in magnitude over time. The object drops 16 feet in the first second, but 80 feet in the last second.

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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