Answer:
The numbers are -14,-13 and -12
Step-by-step explanation:
<u><em>The correct question is </em></u>
Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?
Let
x ----> the first consecutive integer
x+1 ---> the second consecutive integer
x+2 ---> the third consecutive integer
we have that
solve for x
apply distributive property
Combine like terms
subtract 8 both sides
Divide by 6 both sides
so
therefore
The numbers are -14,-13 and -12
<em>The answer is</em><em> $300</em><em>......</em>
Answer:
a
Step-by-step explanation:
because I just think its a
Then we will multiply both sides of the equation by 2 π :
x + π ( 1 - x ) = 0
x + π - π x = 0
x ( 1 - π ) = - π / · ( - 1 )
x ( π - 1 ) = π
x = π / ( π - 1 )