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3 years ago

3. What is the length of side a rounded to the nearest tenth of a centimeter?

Mathematics

1 answer:

nlexa [21]3 years ago

3 0

Answer:

a=10

Step-by-step explanation:

a^2+b^2=c^2

8 is b

12.8 is c

a^2+64=163.84

a^2=99.84

a=√99.84

a=10

Hope this helps!

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E line plot below shows the amount of water Rickayla drinks in 10 days. Part a: how many cups of water did Rickayla drink in 10

Levart [38]

Answer:

$Total = 23\frac{1}{4}$ cups

Step-by-step explanation:

Incomplete question.

See attachment for line plot

Required

Total cups drank in 10 days

The number of x at the top of each dataset represent the frequency (i.e. number of cups) drank on that day.

To get the total, we simply multiply this frequency by the accompanying dataset.

So, we have:

$Total = 2 * 1\frac{1}{2} + 1 * 1\frac{3}{4} + 2 * 2 + 2 * 2\frac{3}{4} + 3 * 3$

Express fractions as improper fraction

$Total = 2 * \frac{3}{2} + 1 * \frac{7}{4} + 2 * 2 + 2 * \frac{11}{4} + 3 * 3$

Evaluate each product

$Total = 3 + \frac{7}{4} + 4 + \frac{11}{2} + 9$

Take LCM

$Total = \frac{12+ 7+16+22+36}{4}$

$Total = \frac{93}{4}$

$Total = 23\frac{1}{4}$

6 0

3 years ago

I'll give you brainliest! Just need help with 5-10! (Least common factors)

umka2103 [35]

Answer:

Step-by-step explanation:

$12,\:30\\\\\mathrm{Prime\:factorization\:of\:}12:\quad 2\times\:2\times\:3\\\mathrm{Prime\:factorization\:of\:}30:\quad 2\times\:3\times\:5\\\\=2\times\:2\times\:3\times\:5\\\\=60$

$6,\:10\\\\\mathrm{Prime\:factorization\:of\:}6:\quad 2\times\:3\\\mathrm{Prime\:factorization\:of\:}10:\quad 2\times \:5\\\\=2\times \:3\times \:5\\\\=30$

$16,\:24\\\\\mathrm{Prime\:factorization\:of\:}16:\quad 2\times \:2\times\:2\times\:2\\\mathrm{Prime\:factorization\:of\:}24:\quad 2\times\:2\times\:2\times\:3\\\\=2\times\:2\times\:2\times\:2\times\:3\\\\=48$

$14,21\\\\\mathrm{Prime\:factorization\:of\:}14:\quad 2\times\:7\\\mathrm{Prime\:factorization\:of\:}21:\quad 3\times\:7\\\\=2\times\:7\times\:3\\\\=42$

$9,15\\\\\mathrm{Prime\:factorization\:of\:}9:\quad 3\times\:3\\\mathrm{Prime\:factorization\:of\:}15:\quad 3\times\:5\\\\=3\times\:3\times\:5\\\\=45$