3. What is the length of side a rounded to the nearest tenth of a centimeter?
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
3. slope of CB = rise/run = 5/12 BF = 5 CF = 12
BF ⊥ DF
DB (seg of two farthest points) = √BF²+DF² = √5²+32² = √1049 = 32.4
4. f(x) = 2x² - 5x -3 vertex : A (h,k) for f(x) = ax² + bx +c
h = - b/2a = - (-5 / 4) = 5/4
f = f(h) = 2*(5/4)² - 5*(5/4) - 3 =25/8 - 25/4 -3 = -49/8
A (5/4 , - 49/8) i.e. (1.25 , - 6.13)
negative root: 2x² - 5x -3 = (2x+1) (x- 3) x = - 1/2 y = 0
B (- 1/2 , 0)
x coordinate of AB: 1/2 (1.25 + -0.5) = 0.375
Since the equation for solving circumference is 2
r, you can see that 2r = 46. Dividing 2 on both sides will give you r, or the radius.
Hope this helped! :)
Hope this helped! :)