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Margaret [11]
3 years ago
13

Best way to tell someone no without being mean

Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

Try to search up euphemisms to help you in an argument where your forced to say no

Step-by-step explanation: In this situation apologize to them and say

I can't do that or no

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Which word best describes the degree of overlap between the two data sets?
solniwko [45]
Hey there! :D

When looking at the data sets, notice that they only overlap in the middle, by a few points. There is overlap, so it isn't "none", it isn't much, so it wouldn't be "high" or "moderate". It would be considered low overlap. 

I hope this helps!
~kaikers
5 0
4 years ago
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Urgent!!!!!!!plzz
Nitella [24]

Answer:

too much reading, can you put more points.

(edit: OML SO SORRY -THOUGHT THIS WAS QUESTIONS)

Step-by-step explanation:

7 0
4 years ago
Buna ,ma puteti ajuta
Ksenya-84 [330]
Cu ce să va ajut?????
5 0
3 years ago
Please help wit all questions! leave work below! if you do this , it will give you 40 points!!
Marta_Voda [28]

Answer:

13. ft per minute is 150. ft per hour is 9,000.

work:

  • 300÷ 2 = 150
  • 150 times 60 min.

14. x ÷ y = feet per minute.

it is this because the time divided by the depth will equal the time that it took.

15. it would be more reasonable to use feet by minute, because of the accuracy of the answers. with measuring it using feet per hour, your answers will be less precise.

16. the distance will double because the proportional relationship says that the distance is 3 km away if thunder is 9 secs apart from lightning.

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7 0
4 years ago
What is the inverse of this function? (Function in photo)
valkas [14]

Given:

The function is

f(x)=-\dfrac{1}{2}\sqrt{x+3},x\geq -3

To find:

The inverse of the given function.

Solution:

We have,

f(x)=-\dfrac{1}{2}\sqrt{x+3}

Put f(x)=y.

y=-\dfrac{1}{2}\sqrt{x+3}

Interchange x and y.

x=-\dfrac{1}{2}\sqrt{y+3}

Isolate the variable y.

-2x=\sqrt{y+3}

(-2x)^2=y+3

4x^2-3=y

y=4x^2-3

Putting y=f^{-1}(x), we get

f^{-1}(x)=4x^2-3

For x\geq -3,

x+3\geq 0

\sqrt{x+3}\geq 0

-\dfrac{1}{2}\sqrt{x+3}\leq 0

f(x)\leq 0

It means for function f(x)\leq 0 and for inverse function x\leq 0 because the range of the function is the domain of inverse function.

Therefore, f^{-1}(x)=4x^2-3 for x\leq 0.

3 0
3 years ago
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