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Yuliya22 [10]
2 years ago
8

4cos^2(65) + 4sin^2(65)​

Mathematics
1 answer:
Anettt [7]2 years ago
7 0

Answer:

im not gonna say anything imma get it wrong

Step-by-step explanation:

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Use the function g(x)=11 to find the following values<br> g(-3)
meriva

Answer: https://www.bing.com/search?q=https%3A%2F%2Fwww.chegg.com%2Fhomework-help%2Fquestions-and...%0A&form=IPRV10

Step-by-step explanation: There you will find your answer

7 0
2 years ago
A bacteria culture begins with eight bacteria which triple in size every week. how many bacteria exist in the culture after four
bija089 [108]
Well, you would have to multiply 8 by whatever factorial of 3, in this case 4 for the number of weeks
The equation is 8 x 3^4 which equals 648

My only thing is that they only triple in SIZE, and not multiply (as in make more of themselves) so technically speaking, there would still be 8 bacteria, just much bigger
3 0
3 years ago
Please answer this correctly
tekilochka [14]
Take the coordinates
Ex.
(-5,-1) and count it on the chart
The first number is your x value and ur second number is ur y
Y= up and down
X= side to side
3 0
3 years ago
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
There are four nickels and six dimes in your pocket. You randomly pick a coin out of your pocket and place it on a counter. Then
Anna71 [15]
The probability of picking a nickel first would be: 4/10
The probability of picking a dime first would be: 6/10
4 0
3 years ago
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