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bonufazy [111]
2 years ago
10

Can someone pls help me??? ​

Mathematics
1 answer:
Sidana [21]2 years ago
7 0

a) Two angles are said to be complementary if their sum is equal to 90°

Given : 2x and 4x are complementary angles

⇒   2x + 4x = 90°

⇒   6x = 90°

⇒   x = 15°

<u>Answer</u>: The two angles are : 30° and 60°

b) Two angles are said to be supplementary if their sum is equal to 180°

Given : x and 5x are supplementary angles

⇒   x + 5x = 180°

⇒   6x = 180°

⇒   x = 30°

<u>Answer: </u>The two angles are : 30° and 150°

c) Two angles are said to be complementary if their sum is equal to 90°

Given : x and x + 50° are complementary angles

⇒   x + x + 50° = 90°

⇒   2x = 40°

⇒   x = 20°

<u>Answer:</u> The two angles are : 20° and 70°

d) If two angles form a linear pair, then the sum of the angles should be equal to 180°

Given : 2x + 10° and 3x + 10° form a linear pair

⇒   2x + 10° + 3x + 10° = 180°

⇒   5x = 160°

⇒   x = 32°

⇒  2x + 10° = 2(32) + 10° = 74°

⇒  3x + 10° = 3(32) + 10° = 106°

<u>Answer:</u> The two angles are 74° and 106°

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Answer:

26.25-7.50 = 18.75

18.75/6.25= 3

She golfed for 3 rounds

Step-by-step explanation:

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3 years ago
Which graph below shows the solutions for the linear inequality y&gt;- 1/3x + 1
aliina [53]

The graph that shows the solutions for the inequality, y > -1/3x + 1 is: C. Graph A.

<h3>How to Find the Graph of a Linear Inequality?</h3>

The inequality sign, ">" means that the graph of the inequality has a dashed line where the shaded part is above the boundary line and the boundary line is dashed or dotted. If "≥" is used, the boundary line would not be dashed or dotted and the shaded area would be above it.

On the other hand, "<" is used when the shaded area is below the boundary line and the boundary line is a dashed line. If "≤" was used, the boundary line won't be dashed or dotted, while the shaded area would be below the boundary line that is not dotted.

Given y > -1/3x + 1, the slope (m) = change in y / change in x is -1/3.

Graph A has a slope of -1/3 and the shaded part is above the boundary line.

Therefore, the graph that shows the solutions for y > -1/3x + 1 is: C. Graph A.

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8 0
2 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap
pantera1 [17]

Answer:

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e \dfrac{dV}{dt}= 20 \ ft^3/min

we know that radius r is always twice the   diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

V = \dfrac{\pi r^2 h}{3}

V = \dfrac{\pi (h/2)^2 h}{3}

V = \dfrac{1}{12} \pi h^3

V = \dfrac{ \pi h^3}{12}

Taking the differentiation of volume V with respect to time t; we have:

\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}

\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}

we know that:

\dfrac{dV}{dt}= 20 \ ft^3/min

So;we have:

20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}

20= 56.25 \pi \times \dfrac{dh}{dt}

\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

8 0
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telo118 [61]

I'd say an outlier. P is separated noticably from the other points and would not considerably affect the slope of the line

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