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irga5000 [103]
3 years ago
12

Given: Lines y and z are parallel, and ABC forms a triangle. Prove: m∠5 + m∠2 + m∠6 = 180° Statements Reasons 1. ABC is a triang

le 1. given 2. y ∥ z 2. given 3. ∠1 ≅ ∠5; ∠3 ≅ ∠6 3. ? 4. m∠1 = m∠5; m∠3 = m∠6 4. def. ≅ 5. m∠1 + m∠2 + m∠3 = m∠LAM 5. ∠ addition postulate 6. m∠1 + m∠2 + m∠3 = 180° 6. def. straight angle 7. m∠5 + m∠2 + m∠6 = 180° 7. substitution Which could be the missing reason in Step 3? alternate interior angles are congruent alternate exterior angles are congruent vertical angles are congruent corresponding angles are congruent

Mathematics
2 answers:
Law Incorporation [45]3 years ago
7 0

Answer:

Step-by-step explanation:

8. Statement

m<5+m<2+m<6=180

Reason

Substitution

Sladkaya [172]3 years ago
4 0
The info I read for the6th time indicates that its possible that angle 3 could be congruent to angle 5 or that angle 2 could congruent to angle 6 I'm honestly not sure just helping to brainstorm
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The dinner check was $78.00.<br>If Erin leaves a 20% tip, how<br>much will the tip be?​
jenyasd209 [6]

Answer:

Step-by-step explanation:

Just calculate 20% of 78.00 or 78.00x0.20=$15.6

8 0
3 years ago
Read 2 more answers
Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to
polet [3.4K]

Answer:

(a) The probability that X is at most 30 is 0.9726.

(b) The probability that X is less than 30 is 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is 0.7406.

Step-by-step explanation:

We are given that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked. A random sample of 200 shafts is taken.

Let X = <u><em>the number among these that are nonconforming and can be reworked</em></u>

The above situation can be represented through binomial distribution such that X ~ Binom(n = 200, p = 0.11).

Here the probability of success is 11% that this much % of all steel shafts produced by a certain process are nonconforming but can be reworked.

Now, here to calculate the probability we will use normal approximation because the sample size if very large(i.e. greater than 30).

So, the new mean of X, \mu = n \times p = 200 \times 0.11 = 22

and the new standard deviation of X, \sigma = \sqrt{n \times p \times (1-p)}

                                                                  = \sqrt{200 \times 0.11 \times (1-0.11)}

                                                                  = 4.42

So, X ~ Normal(\mu =22, \sigma^{2} = 4.42^{2})

(a) The probability that X is at most 30 is given by = P(X < 30.5)  {using continuity correction}

        P(X < 30.5) = P( \frac{X-\mu}{\sigma} < \frac{30.5-22}{4.42} ) = P(Z < 1.92) = <u>0.9726</u>

The above probability is calculated by looking at the value of x = 1.92 in the z table which has an area of 0.9726.

(b) The probability that X is less than 30 is given by = P(X \leq 29.5)    {using continuity correction}

        P(X \leq 29.5) = P( \frac{X-\mu}{\sigma} \leq \frac{29.5-22}{4.42} ) = P(Z \leq 1.70) = <u>0.9554</u>

The above probability is calculated by looking at the value of x = 1.70 in the z table which has an area of 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is given by = P(15 \leq X \leq 25) = P(X < 25.5) - P(X \leq 14.5)   {using continuity correction}

       P(X < 25.5) = P( \frac{X-\mu}{\sigma} < \frac{25.5-22}{4.42} ) = P(Z < 0.79) = 0.7852

       P(X \leq 14.5) = P( \frac{X-\mu}{\sigma} \leq \frac{14.5-22}{4.42} ) = P(Z \leq -1.70) = 1 - P(Z < 1.70)

                                                          = 1 - 0.9554 = 0.0446

The above probability is calculated by looking at the value of x = 0.79 and x = 1.70 in the z table which has an area of 0.7852 and 0.9554.

Therefore, P(15 \leq X \leq 25) = 0.7852 - 0.0446 = 0.7406.

5 0
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Arlecino [84]

Step-by-step explanation:

We get two equations here. One for the area and one for the perimeter. The area gives us x×y=50. The perimeter, if we have a rectangle, x+y+x+y=30=2x+2y. For this to work we need to make a simple expression for x or y. Let's go with x here. 2x+2y=30 so x=15-y. if we fill that in the other equation we get (15-y)×y=50 (see picture). y=5 or y=10. If we fill in x×5=50 we get x=10 and vice versa. So the dimensions are 5 centimeters by 10 centimeters

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If –3x + y = -7 is a true equation, what would be the value of -3x + y - 2?
seropon [69]

Answer:

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Step-by-step explanation:

-3x+y=-7

-3x+y-2

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barxatty [35]

Answer:

D. 216 cubic centimetres.

Step-by-step explanation:

The answer is D, because 6 to the 3rd power is 216.  therefore, if the side length is 6, the answer is 216.

7 0
3 years ago
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