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AURORKA [14]
3 years ago
5

Suppose that the width of a rectangular garden is (6 − 2√3) ft. And the length of the garden is (3 + √3) ft. (a) Find the area o

f the garden in simplest radical form. (2 points)
Mathematics
1 answer:
kirill115 [55]3 years ago
3 0

Answer:

A = 12 feet²

Step-by-step explanation:

Given that,

The width of a rectangular garden is (6 − 2√3) ft.

The length of the garden is (3 + √3) ft.

We need to find the area of the garden. The area of a rectangle is given by :

A = lb

Put all the values,

A = (6 − 2√3)(3 + √3)

A = 12 feet²

So, the area of the garden is equal to 12 feet².

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3 0
3 years ago
A 16 -foot ladder is leaning on a tree. The bottom of the ladder on the ground at a distance of 6 feet from the base of the tree
Dima020 [189]

Answer:

14.8 feet

Step-by-step explanation:

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the angles of a quadrilateral 80° hundred degrees hundred degrees and 80 degrees in this order what kind of quadrille has this s
sergij07 [2.7K]
<span>This isosceles trapezoid
</span>
As Most conveniently , it is to prepare a drawing , in line with the conditions of the problem . The angles of 80° adjacent to each other , then it will angles are 100° . The first that comes to mind at the thought figure is the isosceles trapezoid .
1 . We draw a straight line ( figure 1 )
2, Na simple we set two angles of 80° ( figure 2 )
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3 years ago
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