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Gelneren [198K]
3 years ago
13

$13,000 was borrowed from two sources, one that charges 15% simple interest and the other that charges 10% simple interest. If t

he total interest at the end of 1 year was $1750, how much money was borrowed from each source?
Mathematics
1 answer:
guajiro [1.7K]3 years ago
5 0

9514 1404 393

Answer:

  • $9,000 at 15%
  • $4,000 at 10%

Step-by-step explanation:

Let x represent the amount borrowed at 15%. Then the amount borrowed at 10% is (13000-x). The interest at the end of the year is ...

  0.15(x) + 0.10(13000 -x) = 1750

  0.05x = 1750 -1300 . . . . . . . . . . . . simplify, subtract 1300

  x = 450(20) = 9000 . . . . . . . . . . multiply by 20

$9,000 was borrowed at 15%; $4,000 was borrowed at 10%.

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Answer:

The amount of jobs from fitting industry shall decline in 5.5 percent from 2015 to 2025.

Step-by-step explanation:

Due to the assumption of a yearly average rate, a linear function model shall be used. The expected amount of jobs (n) after a certain amount of years (t) is given by the following formula:

n = n_{o} + \frac{\Delta n}{\Delta t}\cdot t

Where:

n_{o} - Initial amount of jobs in pipe fitting industry, measured in thousands.

\frac{\Delta n}{\Delta t} - Average yearly rate, measured in thousands per year. (A decline is indicated by a negative sign)

If n_{o} = 546.5, t = 2025-2015 = 10\,years and \frac{\Delta n}{\Delta t} = -3\,\frac{1}{years}, then:

n = 546.5+\left(-3\,\frac{1}{year}\right)\cdot (10\,years)

n = 516.5

The percent change in jobs from pipe fitting industry is calculated as follows:

\%n = \left(1-\frac{n}{n_{o}}\right)\times 100\,\%

\% n = \left(1-\frac{516.5}{546.5}\right)\times 100\,\%

\%n = 5.5\,\%

The amount of jobs from fitting industry shall decline in 5.5 percent from 2015 to 2025.

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Answer:

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