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3 years ago

A tree was 17 feet tall when it was planted. It grew 8 times that height in 15 years.

Mathematics

2 answers:

Nataliya [291]3 years ago

6 0

Answer:

A. 119 feet

Step-by-step explanation:

the height of tree right now =

17 × 8 = 136 feet

the differences = 136 -17 = 119 feet

professor190 [17]3 years ago

4 0

Answer:

A. 119

Step-by-step explanation:

In 15 years, the tree grew to a height of 8 x 17 = 136 feet. Since it was planted at a height of 17 feet, the tree grew 136-17=119 feet.

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What is the mean of integers<br> -16,-27,21,-19,14,-3<br> -

Lelu [443]

Answer:

-5

Step-by-step explanation:

-16+(-27)+21+(-19)+14+(-3)/6

-30/6

=-5

3 0

3 years ago

Question 1 Arecipe for a chicken and rice dinner calls for 3 cups of rice for every 2 pounds of chicken. Select the true stateme

lina2011 [118]

Answer:

The ratio of pounds of chicken to cups of rice is 2 to 3.

Step-by-step explanation:

3 rice: 2 chicken

3:2 ratio

can be written either number first

3 0

3 years ago

Rosalinda examined the angles at right and wrote the equation below.

jeyben [28]

a. Does her equation make sense? If so, explain why her equation must be true. If it is not correct, determine what is incorrect and rewrite the equation.

b. If you have not already done so, solve her equation, clearly showing all your steps. What are the measures of the two angles?

c. Verify that your answer is correct.

The figure is attached below

Given : (2x+1) + (x-10) = 90

(a) Yes , the equation make sense because right angle is 90 degree. Also two angles make up 90 degree.

(b) solve for x, (2x+1) + (x-10) = 90

2x+1 + x-10 = 90 ( combine like terms)

3x -9 = 90 (add 9 on both sides)

3x = 99

x = 33

One angle is 2x+1 = 2(33) +1 = 67 degrees

Another angle = x-10 = 33-10 = 23 degrees

67 + 23 = 90

So verified

7 0

3 years ago

Which of the following are identities? check all that apply.

Feliz [49]

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

$(a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x$

$(b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)$

$(c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow 3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x$

$(d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x$

Thus, all the identities are correct.

4 0

3 years ago

HI CAN I PLEASE GET SOME HELP PLEASE THANK YOU I WOULD APPRECIATE IT HOW MANY SOLUTIONS ARE THERE TO THIS NONLINEAR SYSTEM!!!! A

viktelen [127]

Answer:

B) one solution

Step-by-step explanation:

The blue line and the red line cross at only one point so there is one solution. It would be no solution if the blue line never crossed the red line and it would be two or possibly more solutions if the lines crossed more than once.

4 0

3 years ago