<span>The fifth power of ten would not be represented.
Each individual digit would be shown as a power of ten.
982 would be the sum of:
9 times 100. (100 is 10 to the second power)
plus
8 times 10. (10 is 10 to the first power.)
plus
2 times 1. (I is 10 to the zero power.)
The only significant digit represented by a zero is the "hundred thousands"
(100,000 is 10 to the fifth power.)</span>
Answer:
this question is missing something
(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
Answer:
Step-by-step explanation:
The PDF of X is
The PDF of Y is
The means of X and Y are respectively,
so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.
Therefore, the PDF of Z is
0.02 can go into 84, 4200 times. Your answer is <u>incorrect</u>, the <u>correct answer</u> is 4200.
