The value of c, the constant of the function y = ax² + bx + c, exists -3.
<h3>What is an equation?</h3>
An equation exists as an expression that indicates the relationship between two or more numbers and variables.
Given that: y = ax² + bx + c
At point (4, 21)
21 = a(4²) + 4b + c .......(1)
At point (5, 32)
32 = a(5²) + 5b + c .........(2)
At points (6, 45)
45 = a(6²) + 6b + c .......(3)
Therefore, the value of a = 1, b = 2 and c = -3.
The value of c, the constant of the function y = ax² + bx + c, exists -3.
To learn more about equations refer to:
brainly.com/question/2972832
#SPJ9
Answer:
Fraction:783/40 Decimal:19.575
Mixed:19 23/40
Step-by-step explanation:
Y = mx+b
-1 = 13/4 (-1) +b
-4/4 + 13/4 = b
9/4 = b
Answer:
Step-by-step explanation:
Given the equation ![\frac{1}{3}(x+9) = -12](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%28x%2B9%29%20%3D%20-12)
Step 1;
Expand the bracket at the right hand side of the equation to have:
![\frac{1}{3}x +\frac{1}{3}(9) = -12\\\frac{1}{3}x+3=-12\\subtracting\ 3\ from\ both\ sides\\\frac{1}{3}x+3-3=-12-3\\\frac{1}{3}x=-15\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7Dx%20%2B%5Cfrac%7B1%7D%7B3%7D%289%29%20%3D%20-12%5C%5C%5Cfrac%7B1%7D%7B3%7Dx%2B3%3D-12%5C%5Csubtracting%5C%203%5C%20from%5C%20both%5C%20sides%5C%5C%5Cfrac%7B1%7D%7B3%7Dx%2B3-3%3D-12-3%5C%5C%5Cfrac%7B1%7D%7B3%7Dx%3D-15%5C%5C)
Taking the reciprocal of both sides:
![\frac{3}{x} = \frac{-1}{15} \\ cross\ multiplying\\-x =45\\x=-45](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7Bx%7D%20%3D%20%5Cfrac%7B-1%7D%7B15%7D%20%5C%5C%20cross%5C%20multiplying%5C%5C-x%20%3D45%5C%5Cx%3D-45)
Answer:
The correct answer is <u>-14</u>
Step-by-step explanation: