The answer would be 0.+0.7+0.01+0.009 hope it helps
Answer:


Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
![\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D)
i)
To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.
We have to make it in steps like follows.
Cube both sides:
![\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E3%3D%5Cleft%28%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D%5Cright%29%5E3)
Simplify the radical with the cube:

Multiply by 2y+9

Simplify:

Operate the parentheses:


Subtract 3y and
:

Factor y out of the left side:

Divide by
:

ii) To find y when x=2, substitute:





Answer:
Boxes sold first week = 104
Boxes sold second week =x+5= 104+5=109
Boxes sold third week = 109 times 2= 218
Step-by-step explanation:
Let x be the number of boxes sold in first week
the girls sold 5 more boxes the second week
So number of boxes sold in second week is x+5
they double the sales of the second week for the third week
So number of boxes sold in third week is 2 (x+5)
Total boxes sold is 431



subtract 15 from both sides

divide by 4 on both sides

Boxes sold first week = 104
Boxes sold second week =x+5= 104+5=109
Boxes sold third week = 104 times 2= 218
Mathrie 134x3= 402 ship names are my specialty:)