Find m < RQP

The standard deviation of a probability distribution is a: A. measure of variability of the distribution B. measure of skewness

GuDViN [60]

Answer:

The standard deviation of a probability distribution is a measure of variability of the distribution.

Step-by-step explanation:

We have been given an incomplete statement. We are asked to complete the given statement.

We know that standard deviation is measure of variability or dispersion of a set of data values.

It tells up how much a data point is spread out from the average or mean of the data set.

Therefore, option A is the correct choice.

4 0

3 years ago

Week 1 2 3 4 5 Water Level (inches) − 1 1 4 1 3 8 2 1 2 − 1 5 8 − 1 3 4 Between which two weeks did the water level change the m

suter [353]

Answer:

The water level change the most in week 3 and week 4

The change = -370 inches

Step-by-step explanation:

Given - Week 1 2 3 4 5

Water Level (inches) − 1 1 4 1 3 8 2 1 2 -1 5 8 -1 3 4

To find - Between which two weeks did the water level change the most? Calculate the change .

Proof -

The formula for change in water level with respect to week be-

Rate of Change in Water Level = Difference in water level / Difference in weeks

Now,

For week 1 and week 2

Rate of change in water level = $\frac{138 - 114}{2 - 1}$ = $\frac{24}{1}$ = 24 inches

Now,

For week 1 and week 3

Rate of change in water level = $\frac{212 - 114}{3 - 1}$ = $\frac{98}{2}$ = 49 inches

Now,

For week 1 and week 4

Rate of change in water level = $\frac{-158 - 114}{4 - 1}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 1 and week 5

Rate of change in water level = $\frac{-134 - 114}{5 - 1}$ = $-\frac{248}{4}$ = -62 inches

Now,

For week 2 and week 3

Rate of change in water level = $\frac{212 - 138}{3 - 2}$ = $\frac{74}{1}$ = 74 inches

Now,

For week 2 and week 4

Rate of change in water level = $\frac{-158 - 138}{4 - 2}$ = $-\frac{296}{2}$ = -148 inches

Now,

For week 2 and week 5

Rate of change in water level = $\frac{-134 - 138}{5 - 2}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 3 and week 4

Rate of change in water level = $\frac{-158 - 212}{4 - 3}$ = $-\frac{370}{1}$ = -370 inches

Now,

For week 3 and week 5

Rate of change in water level = $\frac{-134 - 212}{5 - 3}$ = $-\frac{346}{2}$ = 173 inches

Now,

For week 4 and week 5

Rate of change in water level = $\frac{-134 + 158}{5 - 4}$ = $\frac{24}{1}$ = 24 inches

∴ we get

The water level change the most in week 3 and week 4

The change = -370 inches

Note :

The highest change means which temperature goes the most change in water level. It can be negative also.

So, We have to take the modulus and then find the highest number.

Here, 370 > 173

So, Highest change occurs in Week 3 and Week 4 but not in Week 3 and Week 5.

7 0

3 years ago

3) Chris wants to order DVD's over the internet. Each DVD costs $15.99 and shipping the entire order

satela [25.4K]

Answer:

He can buy 5 DVD's. (Brainliest please)

4 0

3 years ago

Read 2 more answers

Brian can type 1 and one-third pages every 20 minutes. How many pages can he type in 2.5 hours? 7.5 pages 10 pages 22.5 pages 20

vladimir2022 [97]

Answer:

10 pages

Step-by-step explanation:

1 and 1/3 pages multiplies by 7.5 brings us to the answer of ten pages

20 minutes goes into 2 and 1/2 hours 7.5 times

5 0

3 years ago

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Given f(x) = x^2-3 and g(x)=x+2/x. Find (g°f)(4)

goblinko [34]

Answer:

15/13

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers