Answer:
The proportions differ from those reported in the survey.
Step-by-step explanation:
The Chi-square goodness of fit test would be used to determine whether the proportions differ from those reported in the survey.
The hypothesis for the test can be defined as follows:
<em>H</em>₀: The proportions does not differ from those reported in the survey.
<em>Hₐ</em>: The proportions differ from those reported in the survey.
Assume that the significance level of the test is, α = 0.01.
The Chi-square test statistic is given by:
Consider the Excel sheet provided.
The Chi-square test statistic value is 191.32.
The <em>p</em>-value of the test is:
The <em>p</em>-value of the test is very small. The null hypothesis will be rejected at 1% level of significance.
Thus, concluding that the proportions differ from those reported in the survey.
1st year= 18000 x 0.85 = 15300
2nd year= 15300 x 0.85 = 13005
3rd year= 13005 x 0.85= 11054.25
-2y>12x-42
y<21-6x
so a is true
The solution to the given differential equation is yp=−14xcos(2x)
The characteristic equation for this differential equation is:
P(s)=s2+4
The roots of the characteristic equation are:
s=±2i
Therefore, the homogeneous solution is:
yh=c1sin(2x)+c2cos(2x)
Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:
yp=Axsin(2x)+Bxcos(2x)
If you take the second derivative of the equation above for yp , and then substitute that result, y′′p , along with equation for yp above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side, sin(2x) , you will find:
A=0
B=−14
Therefore,
yp=−14xcos(2x)
For more information about differential equation, visit
brainly.com/question/18760518
Hope this helps you with your questions.
