Can Someone Please Help With my homework

Are these triangles similar, if so how do I prove it(SSS,AA or SAS)?

spin [16.1K]

Answer:

There isn't a way to prove that the triangles are similar.

Explanation:

Two triangles are similar if they have the same interior angles and the corresponding sides are proportional.

So, to prove that the triangles are similar we can use:

SSS: The three corresponding sides are proportional

SAS: Two sides are proportional and the angle between them is equal

AA: Two angles have the same measure.

In this case, the yellow angles are equal because they are vertically opposite. They are formed by two lines that intersect.

On the other hand, the side with length 3.6 is corresponding with the side with length 9 but the side with length 4.8 is not corresponding with the side with length 12.

Then, there isn't a way to prove that the triangles are similar.

3 0

9 months ago

Find the intercept of g(n)=-2(3n-1)(2n+1)

vaieri [72.5K]

To find the intercepts of this give function of g(n), we have to find both the points present on the axis. That is, X-Intercept axial or axis point and the Y-Intercept axial or axis point and apply the zero factor principle to get the actual points on the graph for both the respective intercepts. Let me make it simpler, by showing the whole process via the LaTeX interpreter equation editor.

The X-Intercept is that actual point present in the graphical interpretation where the Y-axis is taken as zero, this makes us to point out the position of X-Intercept points on its X-axis and Y-axis. Take the variable "n" as the variable of "x", it will not change any context or such, we can take any variables for calculations, it does not hinder the processing of Intercepts for the axial points on a graph.

$\boxed{\mathbf{\therefore \quad -2(3x - 1)(2x + 1) = 0}}$

By the zero factor principle, both of them can be separately calculated as a zero on their either sides of the expression.

$\mathbf{\therefore \quad 3x - 1 = 0}$

$\mathbf{3x - 1 + 1 = 0 + 1}$

$\mathbf{3x = 1}$

$\mathbf{\dfrac{3x}{3} = \dfrac{1}{3}}$

$\mathbf{\therefore \quad x = \dfrac{1}{3}}$

Similarly, for the second X-Intercept point for the value of 0 in the Y-axis or Y axial plane in a 2 dimensional Graphical representation is going to be, As per the zero factor principle:

$\mathbf{\therefore \quad 2x + 1 = 0}$

$\mathbf{2x + 1 - 1 = 0 - 1}$

$\mathbf{2x = - 1}$

$\mathbf{\dfrac{2x}{2} = \dfrac{- 1}{2}}$

$\mathbf{\therefore \quad x = -\dfrac{1}{2}}$

Then the X-Intercept here becomes with our provided points as:

$\boxed{\mathbf{\underline{X-Intercept: \quad \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg)}}}$

Therefore, for our Y-Intercept axial point the X axial plane will instead turn out to be a value with zero on a Graphical representation to obtain the actual points for Y-axis and the Y-Intercept for x = 0 as a point on the graph itself.

Just substitute the value of "0" in "x" axis as a variable on the provided expression. Therefore:

$\boxed{\mathbf{= -2(3 \times 0 - 1) (2 \times 0 + 1)}}$

$\mathbf{y = - 2 (0 - 1) (0 + 1)}$

$\mathbf{y = - 2 (- 1) (0 + 1)}$

$\mathbf{y = - 2 (- 1) \times 1}$

$\mathbf{y = 2 \times 1 \times 1}$

$\mathbf{\therefore \quad y = 2}$

Then, the Y-Intercept would definitely be as per the X-axis lying on the point of zero.

$\boxed{\mathbf{\underline{Y-Intercept: \quad \big(0, \: 2 \big)}}}$

The final coordinating points for X-Intercept and Y-Intercept for their X-axis and Y-axis will be.

$\boxed{\mathbf{\underline{X \: Intercepts: \: \: \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg); \: \: Y \: Intercepts: \: \: \big(0, \: 2 \big)}}}$

Hope it helps.

6 0

3 years ago

The table shows the cost y (in dollars) of renting x movies<br><br> Someone please awnser this

Semenov [28]

D: is 9. and you would graph it at 2,9

7 0

2 years ago

I BEEN STUCK ON THIS FOR SO LONG

stiks02 [169]

Answer:

8 percent

Step-by-step explanation: