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Temka [501]
2 years ago
5

Cecily is comparing two checking accounts. Checking account A has a monthly fee of $16 and a per-check fee of $0.08, while check

ing account B has monthly fee of $14 and a per-check fee of $0.12. She want to know how many checks she would need to write per month for the accounts to charge the same amount in fees.
Part III: What equation can be set up to solve for the number of checks Cecily would need to write per month for the accounts to charge the same amount in fees?

Part IV: How many checks would Cecily need to write per month for the accounts to charge the same amount in fees?​
Mathematics
1 answer:
-BARSIC- [3]2 years ago
5 0

Part 3

Checking account A has a monthly fee of $16 and a per-check fee of $0.08

If she writes x checks, where x is some nonnegative whole number, then she is charged an additional 0.08x dollars on top of the 16 dollar fee.

The total cost of checking account A is 0.08x+16 dollars.

The total cost of account B is 0.12x dollars for similar reasoning. We don't have a monthly fee, but the cost per check is higher.

Set the two expressions equal to one another to get your answer.

Answer:  0.08x+16 = 0.12x

==============================================

Part 4

Let's solve the equation we set up in part 3

0.08x+16 = 0.12x

16 = 0.12x-0.08x

16 = 0.04x

0.04x = 16

x = 16/0.04

x = 400

If Cecily wrote 400 checks per month, then the cost of each account would be the same.

For account A, it would cost her 0.08*x+16 = 0.08*400+16 = 48 dollars

For account B, it would cost her 0.12*x = 0.12*400 = 48 dollars.

Answer: 400 checks per month

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The sum of a rational number and an even integer is rational. A) Always True B) Sometimes True C) Usually True D) Never True
SOVA2 [1]
I think that the sum will always be a rational number
let's prove that


<span>any rational number can be represented as a/b where a and b are integers and b≠0

</span>and an integer is the counting numbers plus their negatives and 0
so like -4,-3,-2,-1,0,1,2,3,4....

<span>so, 2 rational numbers can be represented as

</span>a/b and c/d (where a,b,c,d are all integers and b≠0 and d≠0)

their sum is
a/b+c/d=
ad/bd+bc/bd=
(ad+bc)/bd

1. the numerator and denominator will be integers
2. that the denominator does not equal 0

alright
1.
we started with that they are all integers
ab+bc=?
if we multiply any 2 integers, we get an integer
<span>like 3*4=12 or -3*4=-12 or -3*-4=12, etc.
</span>even 0*4=0, that's an integer
the sum of any 2 integers is an integer
like 4+3=7, 3+(-4)=-1, 3+0=3, etc.
so we have established that the numerator is an integer

now the denominator
that is just a product of 2 integers so it is an integer


<span>2. we originally defined that b≠0 and d≠0 so we're good

</span>therefore, the sum of any 2 rational numbers will always be a rational number <span>is the correct answer.</span>
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3 years ago
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Step-by-step explanation:

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7 0
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Write the equation of a line that is perpendicular to y=5 and that passes through the point (−7,−5)
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A circular quilt is made from 113.04 square feet of fabric. How much trim is needed to go around it’s edge?
erik [133]

Hey there!

We are looking for the circumference of the circle, which is the distance around it. We are given the area, which is the radius squared times pi.

First, we need to undo the area to find our radius.

113.04/3.14=36

We square root this to find the radius.

√36=6

Our radius is six. To find the circumference, we need to multiply the diameter by pi. The diameter is twice the radius.

6*2=12

12*3.14=37.68

Therefore, we will need 37.68 feet of trim to around the edge of the quilt.

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6 0
3 years ago
If tan0=-3/4 and 0 is in quadrant IV, cos20= (33/25, -17/25, 32/25, 7/25, 24/25?) and tan20= (24/7, -24/7, 7/25, -7/25, 13/7, -1
Oksana_A [137]

Answer:

  • cos(2θ) = 7/25
  • tan(2θ) = -24/7

Step-by-step explanation:

Sometimes, it is easiest to let a calculator do the work. (See below)

__

The magnitude of the tangent is less than 1, so the reference angle will be less than 45°. Then double the angle will be less than 90°, so will remain in the 4th quadrant, where the cosine is positive and the tangent is negative.

You can also use the identities ...

  cos(2θ) = (1 -tan(θ)²)/(1 +tan(θ)²)

  cos(2θ) = (1 -(-3/4)²)/(1 +(-3/4)²) = ((16-9)/16)/((16+9)/16)

  cos(2θ) = 7/25

__

  tan(2θ) = 2tan(θ)/(1 -tan(θ)²) = 2(-3/4)/((16-9/16) = (-6/4)(16/7)

  tan(2θ) = -24/7

3 0
3 years ago
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