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Ipatiy [6.2K]
3 years ago
12

Write a real world problem for the equation y=3/5x+100

Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:

is this for a test?

Step-by-step explanation:

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GIVING BRAINLIEST!!!
Blababa [14]

Answer:

a) -4

b) 2

Step-by-step explanation:

a) f(-2) = 3*-2 + 2 = -4

b) f(x) = 8

3x + 2 = 8

3x = 8 -2

3x = 6

x = 6/3

x = 2

7 0
2 years ago
HELP I WILL GIVE BRAINLIEST
ddd [48]
False because it is only showing the quarter
4 0
3 years ago
चुनाव आयोग के कार्यों को लिखिए।​
AVprozaik [17]

Answer:

भारत निर्वाचन आयोग (अंग्रेज़ी: Election Commission of India) एक स्वायत्त एवं अर्ध-न्यायिक संस्थान है जिसका गठन भारत में स्वतंत्र एवं निष्पक्ष रूप से विभिन्न से भारत के प्रातिनिधिक संस्थानों में प्रतिनिधि चुनने के लिए किया गया था। भारतीय चुनाव आयोग की स्थापना 25 जनवरी 1950 को की गयी थी।

7 0
2 years ago
Solve by using square roots. ​ 6x^2−27=39
Bingel [31]

Answer:

Simplifying

x = 11

Step-by-step explanation:

Simplifying

6x + -27 = 39

Reorder the terms:

-27 + 6x = 39

Solving

-27 + 6x = 39

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '27' to each side of the equation.

-27 + 27 + 6x = 39 + 27

Combine like terms: -27 + 27 = 0

0 + 6x = 39 + 27

6x = 39 + 27

Combine like terms: 39 + 27 = 66

6x = 66

Divide each side by '6'.

x = 11

Simplifying

x = 11

6 0
3 years ago
Represent the following expressions as a power of the number a (a≠0): c ((a2)−2)5÷(a4a)3
s2008m [1.1K]

Answer:

1/a²⁷

Step-by-step explanation:

Given: $ \frac{((a^2)^{-2})^5}{a^4.a^3} $

We know that when the bases are same the powers can be added. i.,e.,

                                           (xᵃ)ᵇ = x ⁽ᵃ ⁺ ᵇ⁾

⇒ $ \frac{((a^2)^{-2})^5}{a^4.a^3} \implies \frac{(a^2)^{-10}}{a^7} $

$  \implies \frac{a^{-20}}{a^7} = a^{-20 - 7} = a^{-27} $

Also, $ \frac{x^a}{x^b} = x^{a - b} $

This is nothing but, $ \frac{1}{a^{27}} $.

Note that $ a $ cannot be zero here. The condition is provided in the question as well.

7 0
3 years ago
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