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Alex73 [517]
3 years ago
10

The Sunny Days Apartment building has a cylindrical, above ground pool in the yard. The radius of the pool is 2 times its height

, and the volume is 3000 cubic feet. How deep is the pool? In other words, what is the height of the pool?
Mathematics
1 answer:
garik1379 [7]3 years ago
3 0

9514 1404 393

Answer:

  6.2 ft

Step-by-step explanation:

The volume of a cylinder is given by ...

  V = πr²h

Here, we have r=2h and V=3000 ft³. Putting these numbers into the formula and solving for h, we get ...

  3000 ft³ = π(2h)²h

  (3000 ft³)/(4π) = h³ . . . . . divide by the coefficient of h³

  h = ∛(750/π) ft ≈ 6.2 ft

The pool is about 6.2 feet deep.

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How do you do <br> (2/3) (-4) (9)
DochEvi [55]

Answer:

Since 3 is evenly divided by 9, we can multiply just one term to get a common denominator. Multiply 2 by 3, and get 6, then we multiply 3 by 3 and get 9.

Step-by-step explanation:

7 0
3 years ago
The height of one square pyramid is 12 m. A similar pyramid has a height of 6 m. The volume of the larger pyramid is 400 m3. Det
valentinak56 [21]
A) <span>Scale factor of the smaller pyramid to the larger pyramid in simplest form:
</span>6 m / 12 m = 1/2 

b) <span>Ratio of the areas of the bases of the smaller pyramid to the larger pyramid:
</span><span>(1/2)^2 = 1/4 </span>

c) <span>Ratio of the volume of the smaller pyramid to the larger:
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4 0
3 years ago
1.Where is the least change in the amount of money earned?
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30 or 3 and 4 weeks hope this helps
6 0
3 years ago
Read 2 more answers
Need answer to 4 and 5
algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $ g_n  = 2 . 3^{n - 1} $

To find the first term, substitute n = 1.

Therefore, $ g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1  $ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3 $ = 6

$ g_3 =  2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9 $ = 18

$ g_4 = 2 . 3^{4  - 1} = 2 . 3^{3} = 2 . 27 $ = 54

$ g_5 =  2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81 $ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $ t_n = \frac{2}{3}t_{n - 1} $

$ t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1  = \frac{2}{3}6 $ = 4

$ t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3} $

$ t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9} $

$ t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27} $

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0
3 years ago
1/2 (x−8)+1=2( 1 8 x−1)
nalin [4]

Answer:

The solution for the given algebraic equation is \frac{ - 2}{71}

Step-by-step explanation:

Given algebraic equation as :

\frac{1}{2} ( x - 8 ) + 1 = 2 ( 18 x - 1 )

Now solving the equation while opening the brackets

So, \frac{1}{2} × x - \frac{1}{2} × 8  + 1 = 2 × 18 x - 2

Or, \frac{x}{2}  - \frac{8}{2}  + 1  = 36 x - 2

or,  \frac{x}{2}  - 4 + 1 = 36 x - 2

or,  \frac{x}{2}  - 3 = 36 x - 2

or,  \frac{x}{2} - 36 x = - 2 + 3

Or,  \frac{x}{2} - 36 x = 1

or, \frac{x - 72 x}{2} = 1

or, \frac{- 71 x}{2} = 1

∴ 71 x = - 2

I.e x = \frac{ - 2}{71}

Hence The solution for the given algebraic equation is \frac{ - 2}{71}    Answer

7 0
3 years ago
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