The equations y = tan^2 (x) and y = 1 are graphed below. According to the graphwhich of the following is part the solution to th
e trigonometric inequality tan^2 (x) < 1 over the interval 0 <= x <= 2pi radians?
2 answers:
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first add
(3a²-5a+5)+(a³-5a²+8)
=3a²-5a+5+a³-5a²+8
=a³-2a3a²-5a²+5+8
=a³-2a²+13
and now,
substract a³-2a²+13 from a²-4a²-9
=7a²-4a²-9-(a³+13)
=7a²-4a²-9-a³+2a²-13
= a³+7a²-4a²+2a²-9-13
=-a³+5a²-22
<h2><u>hope</u><u> it</u><u> helps</u></h2>