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andrey2020 [161]
3 years ago
13

The equations y = tan^2 (x) and y = 1 are graphed below. According to the graphwhich of the following is part the solution to th

e trigonometric inequality tan^2 (x) < 1 over the interval 0 <= x <= 2pi radians?

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
8 0

Answer: a

Step-by-step explanation:

just took test edg2020

Anastaziya [24]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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Can someone answer this for me pls and thank you
kherson [118]

x in terms of b:

-2(bx - 5) = 16

-2bx + 10 = 16

-2bx =  6

    x = 6 / -2b

    x = -3/b

--------------------------------

when b = 3 then

-2(3x - 5) = 16

-6x + 10 = 16

-6x =  6

  x = -1

Answer

The value of x in terms of b is -3/b

The value of x when b is 3 is -1

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tatuchka [14]
0.21 is greater than 0.12 because it in the 20s
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The base diameter and the height of a cone are both
WITCHER [35]

Answer:

11/ 42. *. X^ 2. * X = I/3 X A * h; if E = 1/3 A

Then the answer is EX

Step-by-step explanation:

Volume of cone= 1/3 * base area * height

= 1/3 * pi* (X/2)^2 * X

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= 22/ 21 * X^3 / 4

= 11/21 *. X^2/ 2. *. X

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= 11/ 42. *. X^ 2. * X

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3 years ago
A. Trong mặt phẳng Oxy , phép quay mỗi vector quanh gốc tọa độ một góc α ngược chiều kim đồng hồ là một ánh xạ tuyến tính . Hãy
AveGali [126]

Answer:

a

Step-by-step explanation:

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