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Andre45 [30]
2 years ago
11

Please help meeeee- look at the figure

Mathematics
1 answer:
melomori [17]2 years ago
7 0

Answer:

somethings not right lm.ao

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.    。    •   ゚  。   .    .      .     。   。 .   .   。      ඞ 。 .    •     •   ゚   villain deku was An Impostor.  。 .   '    1 I
Pie

Answer:

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
F) Two numbers are in the ratio 5:4. If they differ by 12, what are the numbers?
Iteru [2.4K]

Answer:

First number = 60 and another number = 48

Step-by-step explanation:

Let two numbers are 5x and 4x.

The two number are differ by 12. We need to find the numbers.

ATQ,

5x-4x = 12

x = 12

Now first number = 5x

= 5(12)

= 60

Other number = 4x

= 4(12)

= 48

Hence, the numbers are 60 and 48.

8 0
3 years ago
Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.
alina1380 [7]

Answer:

The answer is x=a^{-1}cb^{-1}.

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element g\in G there exist another element, denoted by g^{-1} such that gg^{-1}=e, where e stands for the identity element of G.

So, given the equality axb=c we make a left multiplication by a^{-1} and we obtain:

a^{-1}axb =a^{-1}c.

But, a^{-1}axb = exb = xb. Hence, xb = a^{-1}c.

Now, in the equality xb = a^{-1}c we make a right multiplication by b^{-1}, and we obtain

xbb^{-1} = a^{-1}cb^{-1}.

Recall that bb^{-1}=e and xe=x. Therefore,

x=a^{-1}cb^{-1}.

6 0
3 years ago
Can you solve it, please
Nimfa-mama [501]
T
T
F
F
Yayyyy that’s the answer
5 0
3 years ago
Read 2 more answers
Convert 11.42424242 … to a rational expression in the form of a over b, where b ≠ 0.
Pavlova-9 [17]

x=11.4242....

100x=1142.4242....

100x-x = 99x = 1131

x=1131/99 = 11 42/99 (unreduced) = 11 14/33 (reduced fraction)

7 0
3 years ago
Read 2 more answers
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