For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
Answer:
-54
Step-by-step explanation:
it is -54 because you must subtract 19 every time.
Answer:
205
Step-by-step explanation:
sorry if im wrong
Answer:
n = 6
Step-by-step explanation:
4n + 2 = 26,
4n = 24,
n = 6
Step-by-step explanation:
(25)^(-0.25) / (25)^(0.25)
= (25)^(-0.5)
= (5)^(-1)
= 1/5 = 0.2.
