Answer:
$14.4
Step-by-step explanation:
I don't quite understand this question, but this is what I think
First, tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>), so if cos(<em>θ</em>) = 3/5 > 0 and tan(<em>θ</em>) < 0, then it follows that sin(<em>θ</em>) < 0.
Recall the Pythagorean identity:
sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1
Then
sin(<em>θ</em>) = -√(1 - cos²(<em>θ</em>)) = -4/5
and so
tan(<em>θ</em>) = (-4/5) / (3/5) = -4/3
The remaining trig ratios are just reciprocals of the ones found already:
sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/3
csc(<em>θ</em>) = 1/sin(<em>θ</em>) = -5/4
cot(<em>θ</em>) = 1/tan(<em>θ</em>) = -3/4
It’s 3.5
use formula the formula
V=lwh
——
3
Answer:
50
Step-by-step explanation:
p/5=10
Your main goal is to isolate p
p/5 = 10, in order to eliminate the 5, multiply 5 on both sides, since it's the inverse of division.
(5)p/5 = 10(5)
p=50
Distribute
-12 -6a = -48
Add 12 to isolate -6a
-6a = -36
Divide by -6 on both sides to isolate a
a = 6
