<span>I is dominant, i is recessive. The A's and B's are just show which allele I is. When there is just one dominant allele, it masks the recessive in blood typing. Remember IA and IB are codominant.
O is always ii
A is IAi (heterozygous) or IAIA (homozygous)
B is IBi (heterozygous) or IBIB (homozygous)
AB is always IAIB
Remember: You get one allele from each parent!
1. Father must be ii, mother must be ii, so all children must be ii.
2. Father is IAIA (the homozygous one), the mother is IBIB, so the only possibility for the children is IAIB, because you get one allele from the father and one from the mother.
3. Father is IAi, mother is IBi, so the children can be any of the blood types, because they can have all the combinations of genotypes.
4. Father is ii, mother is IAIB. Children can only be IAi or IBi.
5. Father is IAIB, mother is IAIB. Children can be IAIA, IBIB, or IAIB.
Example of Punnett square:
3. Father is type A, heterozygous, mother is type B, heterozygous
Father must be IAi (heterozygous)
Mother must be IBi (heterozygous)
_______IA ____ i
IB____ IBIA____IBi
i _____ IAi______ii
Sorry, that was difficult on here, hope it's understandable.
The father's alleles run across the top, the mother's are on the side, you follow to where they meet to find the possibilities for the children. IBIA (AB blood type), IBi (B), IAi (A), and ii (O) are the possibilities in this case.
Hope that helps!</span>
Answer:
C
Explanation:
Diversity is based on the practice and experience you have with a variety of different ethnic backgrounds
Answer:
DNA polymerases from human cells will denature under these conditions.
Explanation:
Under the PCR conditions described, DNA polymerase from <em>T. aquaticus </em>would be more effective than DNA polymerase from human cells. This is due to the higher optimal temperature of DNA polymerase from <em>T. aquaticus. </em>
The number of protons in the nucleus of the atom.
The answer is Glycolysis. Glycolysis is the first stage of Respiration that happens in the cytoplasm of the cell. In this process, a 6-carbon sugar molecules is broken down to form 2 molecules of 3-carbon pyruvate. The process of Glycolysis generates ATP in the presence of oxygen.