Answer:
A
Step-by-step explanation:
Answer:
A
Step-by-step explanation:

The perimeter of ΔXYZ is 126 units.
Solution:
Given ΔPQR
ΔXYZ.
In ΔPQR,
PQ = 5, QR = 10, PR = 6
In ΔXYZ, XY = 30
Perimeter of ΔPQR = PQ + QR + PR
= 5 + 10 + 6
= 21
Perimeter of ΔPQR = 21
To find the perimeter of ΔZYZ:
If two triangles are similar then the ratio of the perimeters of two similar triangles is same as the ratio of their corresponding sides.


Do cross multiplication, we get
⇒ 5 × Perimeter of ΔXYZ = 30 × 21
⇒ 5 × Perimeter of ΔXYZ = 630
Divide by 5 on both sides of the equation.
⇒ Perimeter of ΔXYZ = 126
Hence the perimeter of ΔXYZ is 126 units.
The answer would be 10.
d=2A
π=2·78.5
π≈9.99746
Answer:
W(2W-19)
Step-by-step explanation:
let length = L
length= L feet
let Width= W
from the question,
twice the width = 2W
then L = 2W-19
the area of the rectangle
Area= length × width
Area= 2W-19×W
Area= 2W^2-19W
Area= W(2W-19)