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Rama09 [41]
4 years ago
11

The diameter of a sphere is 16 in. What is the sphere's volume? Round to the nearest tenth, if necessary. A) 971.7 in3 B) 1072.3

in3 C) 1137.4 in3 D) 2144.7 in3
Mathematics
1 answer:
statuscvo [17]4 years ago
3 0
Volume of sphere = 4/3πr³

r is radius.

Radius = diameter/2 = 16/2 = 8

Volume = 4/3(3.14)(8)³
Volume = 2143.57

Rounded to nearest tenth would be 2144.7 in³

The answer is D.

Hope this helps :)
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A rectangular football field is 64 meters wide and 100 maters long. A player runs from one corner of the field in a diagonal lin
Dimas [21]

Answer:

119 or 118.726577

Step-by-step explanation:

We should use the Pythagorean Theorem to solve this problem.

a^2+ b^2=c^2

64^2+100^2=c^2

4096+10000=14096

c^2=14096

c=\sqrt{14096}14096

And the root of 14096 is 118.726577.

So the Answer is About 119 meters, or 118.726577

hope this helps!

3 0
3 years ago
A farmer had 90 black sheep and 10 white ones. What fraction of the flock is black?
vodka [1.7K]

Answer:

90%

Step-by-step explanation:

5 0
3 years ago
Point A is located at (3, 4) and is translated right five units and up three units. What is the new location of point A?
hodyreva [135]
(8,7) because 3+5 =8 and 4+3=7
8 0
3 years ago
Read 2 more answers
Using simple linear regression, calculate the trend line for the historical data. say the x axis is april = 1, may = 2, and so o
OverLord2011 [107]
Given a table of historical demand for a product as follows:

\begin{tabular}
{|c|c|}
 &Demand\\[1ex]
April&60\\
May&55\\
June&75\\July&60\\August&80\\September&75\\
\end{tabular}

The linear regression equation is given by

\hat{Y}=bx+a

where:

b= \frac{n\Sigma xy-\Sigma x\Sigma y}{n\Sigma x^2-(\Sigma x)^2}
and
a= \frac{1}{n} (\Sigma y-b\Sigma x)

We calculate the required values using the following table, where
<span>April = 1, May = 2, and so on.

\begin{tabular} &#10;{|c|c|c|c|}&#10;X &Y&X^2&XY\\[1ex] &#10;1&60&1&60\\ &#10;2&55&4&110\\ &#10;3&75&9&225\\&#10;4&60&16&240\\&#10;5&80&25&400\\&#10;6&75&36&450\\[1ex]&#10;\Sigma X=21&\Sigma Y=405&\Sigma X^2=91&\Sigma XY=1,485 &#10;\end{tabular}

Thus,

b= \frac{6(1,485)-21(405)}{6(91)-(21)^2} \\  \\ = \frac{8,910-8,505}{546-441} = \frac{405}{105}  \\  \\ \approx3.86

and

a= \frac{1}{6} (405-(3.86)(21)) \\  \\ = \frac{1}{6} (405-81)= \frac{1}{6} (324) \\  \\ =54

Therefore, the </span><span>trend line for the historical data is given by \hat{Y}=3.86x+54</span>
7 0
4 years ago
1. A computer technician charges a flat fee of $35 to repair a computer in addition to an hourly rate of $22.50. The technician
Misha Larkins [42]

1. Multiply the hourly rate by the number of hours worked ( 22.5h) add that to the flat fee ( 22.5h +35) and that needs to be equal to or greater than what he expects to make:

A. 22.5h + 35 ≥ 215 , with a solution of h ≥ 8

2. Same method as number 1:

C. $3 + 1.80m ≤ $25

3. Each fraction would need 1 negative sign and have the same numerator and denominator, so the answer would be B.6/-7

8 0
3 years ago
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