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Leto [7]
3 years ago
8

What are the coordinates of the point on the directed line segment from (3, 3) to (7,−5) that partitions the segment into a rati

o of 5 to 3
Mathematics
1 answer:
Annette [7]3 years ago
4 0

Answer:

The coordinates of the point is (5.5, -2)

Step-by-step explanation:

Okay, what we want to do here is to get the point that divides the line that joins the points (3,3) to (7,-5) in the ratio 5 to 3

Generally, given the ratio a:b and we want to divide the line joining the points (x1,y1) and (x2,y2) in that ratio, we use the condensed formula below;

Let’s call the point dividing the line in the given ratio z.

The coordinates of Z is;

{(bx1 + ax2)/(a+b), (by1 + ay2)/(a+b)}

In this question (x1,y1) = (3,3)

While (x2,y2) = (7,-5)

while a:b = 5:3

Substituting these values into the coordinate equation for point z, we have ;

{((3(3) + 5(7))/(5+3), ((3)(3) + 5(-5))/(5+3)}

= {44/8 , -16/8} = {5.5, -2}

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Answer:

A. x + y = 5

Step-by-step explanation:

The slope of the equation is equal for parallel lines,

; Slope = (-1)

;Use the formula

(y - y(coordinate of the given point)) = slope × [(x - x(coordinate of the given point)]

; y - 1 = (-1)(x - 4)

; y - 1 = -x + 4...then move the variable (x) to the left hand side and then move (-1) to the right hand side

; x + y = 4 + 1

; Hence,

; x + y = 5

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Which equation represents the relationship shown in the table?
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You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
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Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

\Rightarrow s=\frac{10-\pi r}{2}

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

A=\pi r^2+ (\frac{10-\pi r}{2})^2

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\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}

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For maximum or minimum \frac{dA}{dr}=0

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\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi

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\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

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\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}

\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

=\frac{20\pi}{4+\pi}

4 0
3 years ago
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