Linear functions parabola mostly things in algebra
A number(p) plus six
six plus a number(p)
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
At 11:50
Step-by-step explanation:
1. Subtract the hours and the minutes separately
12: 20
<u>- 0</u>: <u> 30</u>
12: -10
2. If the minutes are negative, subtract 1 from the hours and add 60 to the minutes.
12: -10
<u> - 1</u>: <u>+ 60
</u>
11: 50
You should remind PJ about her deliveries at 11:50.
Answer:
it is odd i think
Step-by-step explanation:
